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3 years ago

How are bacteria ,a rose and a elephant alike

Chemistry

2 answers:

Nady [450]3 years ago

8 0

They all face the characteristics of life, they are all living, and they all have cells.

Amiraneli [1.4K]3 years ago

7 0

Out of the following given choices;

They are all made of eukaryotic cells.

They are all made of prokaryotic cells.

They are all organisms made of cells.

They all reproduce in the same way.

The answer is They are all organisms made of cells. The cell is the basic unit of a living organism. A cell is a structure that is bound by a membrane and contains organelles and DNA (that contains coded instruction on how the cell should behave). While a bacterium has one cell that functions on its own, a rose and an elephant are higher organisms with numerous cells that function together.

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Many bacteria cannot reproduce and cooler temperatures in our destroyed at high temperatures. How do you humans take advantage o

12345 [234]

freezer and refrigerator too cold for most bacteria to grow .oven too hot for bacteria to survive

3 0

3 years ago

10) How many grams are there in 1.00 x 10^24 molecules of BC13?

lana66690 [7]

194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

Explanation:

In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

It is known that 1 moles of any element has 6.022×10²³ molecules.

Then 1 molecule will have $\frac{1}{6.022*10^{23} }$ moles.

So $1*10^{24} molecules = \frac{1*10^{24} }{6.022*10^{23} } =1.66 moles$

Thus, 1.66 moles are included in BCl₃.

Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

As it is known as 1 mole contains molecular mass of the compound.

As the molecular mass of BCl₃ will be

$Molecular mass of BCl_{3}= Mass of Boron + (3*Mass of chlorine)$

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.

Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.

$grams of BCl_{3}=Molar mass of BCl_{3}*Number of moles$

$grams of BCl_{3}=117.17*1.66=194.5 g$

So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

3 0

4 years ago

What is the poH of a<br> 2.6 x 10-6 M H+ solution?<br> pOH = [?]

KatRina [158]

Answer:

pOH = 8.41

Explanation:

From the question given above, we obtained the following information:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pOH =?

Next, we shall determine the pH of the solution. This can be obtained as follow:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pH =?

pH = – Log [H⁺]

pH = – Log (2.6×10¯⁶)

pH = 5.59

Finally, we shall determine the pOH of the solution. This can be obtained as follow:

pH = 5.59

pOH =?

pH + pOH = 14

5.59 + pOH = 14

Collect like terms

pOH = 14 – 5.59

pOH = 8.41

Therefore, the pOH of the solution is 8.41

5 0

3 years ago

Read 2 more answers

Look at the diagram of a fuel cell below.

Ymorist [56]

I’m pretty sure it’s abode and cathode

4 0

3 years ago

Read 2 more answers

Not sure how to do this

faust18 [17]

Answer:

0.0991 M

Explanation:

Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.

H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O

Step 2: Calculate the moles of oxalic acid

The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:

$0.153g \times \frac{1mol}{90.03g} = 1.70 \times 10^{-3} mol$

Step 3: Calculate the moles of sodium hydroxide

The molar ratio of H₂C₂O₄ to NaOH is 1:2.

$1.70 \times 10^{-3} molH_2C_2O_4 \times \frac{2molNaOH}{1molH_2C_2O_4} = 3.40 \times 10^{-3} molNaOH$

Step 4: Calculate the molarity of sodium hydroxide

$\frac{3.40 \times 10^{-3} mol}{34.3 \times 10^{-3} L} = 0.0991 M$

4 0

4 years ago