Each junior receives 93 score on the test. It is also the average score of the juniors.
Given Information
It is given that 10% of the strength of the class consists of juniors and 90% consists of seniors.
Let us assume the total strength of the class is 100, then,
Number of seniors = 90
Number of juniors = 10
It is also given that the average score of the class = 84
And, average score of the seniors = 83
Another given information is that all the juniors all received the same score, which is their average score. Let it be x.
Average Score of Juniors
Total marks obtained by the seniors = Number of seniors × Average score of seniors
= 90 × 83
= 7470
Total marks obtained by the juniors = Number of juniors × Average score of juniors
= 10x
Average marks on the test = Total marks / Total number of students
⇒ 84 = (7470 + 10x)/100
⇒ 84 × 100 = 7470 + 10x
⇒ 10x + 7470 = 8400
⇒ 10x = 8400-7470
⇒ 10x = 930
⇒ x = 930/10
⇒ x = 93
Thus, each junior scores 93 on the test.
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7, to find the mean add up all the numbers and then subtract by the amount of Humber a you added.
For example, 1,3,8,10 added together is 22. We added four numbers together, so divide by 4. The mean of 1,3,8,10 is 5.5
Answer:
choice A) circumference = 31.4 ft
Step-by-step explanation:
circumference = 3.14(10)
circumference = 31.4 ft
