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3 years ago

Write an equation for (-1,-2),(-3,-4)

Mathematics

1 answer:

Marina86 [1]3 years ago

7 0

Answer:

y=x+1

Step-by-step explanation:

First find the slope by subtracting the y values from both points and dividing it by the subtraction of the x values from both points:

-4--2/ -3--1= -2/-2= 1

so the slope is 1

Now find the y-intercept by plugging in the x and y from one of the points into the equation y=x+b

-3=-4+b

1=b

now plug the slope and y intercept in:

y=x+1

hope this helps :D

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Which of these statements is correct?

tatuchka [14]

Answer:

The system of linear equations 8x - 3y = 10 and 16x - 6y = 22 has no solution is correct.

Step-by-step explanation:

1) The system of linear equations 6x - 5y = 8 and 12x - 10y = 16 has no solution.

Solve these linear equations simultaneously

Step 1 : Find y in terms of x from any one equation

6x - 5y = 8

y = 8 - 6x

-5

Step 2 : Substitute y in terms of x from step 1 in the second equation.

16x - 6y = 22

16x - 6 (8 - 6x) = 22

-5

80x - 48 + 36x = 22 x -5

94x = 43

x = 0.457

This statement is incorrect as it does have a solution.

2) The system of linear equations 7x + 2y = 6 and 14x + 4y = 16 has an infinite number of solutions.

Solve these linear equations simultaneously

Step 1 : Find y in terms of x from any one equation

7x + 2y = 6

y = 6 - 7x

Step 2 : Substitute y in terms of x from step 1 in the second equation.

14x + 4y = 16

14x + 4(6 - 7x) = 16

14x + 12 - 14x = 16

0 ≠ 4

This statement is not true as there are no solutions.

3) The system of linear equations 8x - 3y = 10 and 16x - 6y = 22 has no solution.

Solve these linear equations simultaneously

Step 1 : Find x in terms of y from any one equation

8x - 3y = 10

x = 10 + 3y

Step 2 : Substitute x in terms of y from step 1 in the second equation.

16x - 6y = 22

16(10 + 3y) - 6y = 22

20 + 6y - 6y = 2

0 ≠ -18

This statement is true because there are no solutions

4) The system of linear equations 9x + 6y = 14 and 18x + 12y = 26 has an infinite number of solutions.

Solve these linear equations simultaneously

Step 1 : Find x in terms of y from any one equation

9x + 6y = 14

x = 14 - 6y

Step 2 : Substitute x in terms of y from step 1 in the second equation.

18x + 12y = 26

18 (14 - 6y) + 12y = 26

8 - 12y + 12y = 26

0 ≠ 18

This statement is incorrect because there are no solutions. It does not have infinite number of solutions.

!!

8 0

3 years ago

Read 2 more answers

Question 1 Determine the midpoint of the segment with endpoint (-9,3) and (7,-8). Question 2

mario62 [17]

Answer:

(-1, -2.5)

Step-by-step explanation:

the midpoint of a segment is $(\frac{x1+x2}{2} ,\frac{y1+y2}{2}$ $)$ , given points (x1, y1) and (x2, y2)

$midpoint=(\frac{-9+7}{2}, \frac{3-8}{2} )$ $= (\frac{-2}{2}, \frac{-5}{2} ) = (-1, -2.5)$

6 0

3 years ago

Read 2 more answers

Please help it is math

olasank [31]

Answer:

A linear function has the form y=mx+b

A line has a proportional relationship if y/x is always the same ratio for any value.

The slope m=(y2-y1)/(x2-x1) for some two points on a line is always constant, else it wouldn't create a line.

A line won't be proportional if you adapt b because the ratio of y/x won't match the slope anymore.

In the end this means all lines with proportional relationships must intersect (0,0) or in other words f(0)=0.

This happens if they have the shape y=mx.

Step-by-step explanation:

hope this helps pls mark me brainliest

4 0

3 years ago

Pls Help! Which graph A,B or C?

julsineya [31]

Answer:

Answer=C

Step-by-step explanation:

6 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

3 0

3 years ago

Write an equation for (-1,-2),(-3,-4)￼

Write an equation for (-1,-2),(-3,-4)