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3 years ago

PLEASE HELP

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

8 0

Yes yes yes yes yes yes yes yes yes yes yes yes yes

Oliga [24]3 years ago

3 0

Yes yes yes yes yes yes

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6,666,666×666,666 /1+2+3+4+5+6+5+4+3+2+1 − 777,777×777,777/1+2+3+4+5+6+7+6+5+4+3+2+1

jeka57 [31]

Answer:

111111 $\times$ 1111110 is the simple expression.

Step-by-step explanation:

The expression to be solved:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}$

First of all, let us solve the first term:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111$

Now, the right term:

$\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111$

So, the expression to be solved becomes:

$1111111\times 111111-111111\times 111111\\\Rightarrow 111111(1111111-1)\\\Rightarrow 111111\times 1111110$

3 0

3 years ago

How would I write that translation rule (right 2, down 10)

Nady [450]

Answer: (2, -10)

Down and left are negative right and up are positive.

7 0

3 years ago

What is the GCF of 11ab + 32ab ?

Diano4ka-milaya [45]

The GCF is of 11ab +32ab is 43ab

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3 years ago

A certain amount of money is shared between

ICE Princess25 [194]

<h3>Hello There !! </h3>

<h3><u>Explanation :- </u></h3>

• Amount received by Rui = 5x = 5 x 11 = $55..

• Amount received by Vishal = 9x = 9 x 11 = $99..

Let the amount received by Rui be 5x..

Then the amount received by Vishal is 9x ..

And by this data = 5x + 44 = 9x ..

4x = 44
x = 44/4 = 11

• Amount received by Rui = 5x = 5 x 11 = $55..

• Amount received by Vishal = 9x = 9 x 11 = $99..

<h3>Hope this helps you..! </h3>

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2 years ago

22x – 54 + 5.736x^4 - 2x^2<br> Standard form

Yuri [45]

Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

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3 years ago