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Triss [41]
3 years ago
7

What 100times100times100

Mathematics
2 answers:
diamong [38]3 years ago
6 0

Answer:

1000000

Step-by-step explanation:

elixir [45]3 years ago
5 0

Answer:

10,00,000

Step-by-step explanation:

10*10*10=10,00,000

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Each parking space will be 19 feet by 8 feet. what is the maximum number of parking spaces that will fit in the lot? 10 30 35 40
vladimir1956 [14]

The maximum number of parking spaces that will fit in the lot given the area of the parking lot is 30.

<h3>what is the maximum number of parking spaces that will fit in the lot? </h3>

The parking lot has the shape of a rectangle. The area of a rectangle is length x width

The area of the available parking space =  length of the lot - [width of the lot - (width of the alley x 2)

80 x (77 - 10 - 10) = 4560 ft²

Maximum number of parking spaces = 4560 / (19 x 8) = 30

Please find attached the complete question. To learn more about how to calculate the area of a rectangle, please check: brainly.com/question/16595449

#SPJ4

4 0
2 years ago
14. In a month-long randomized comparative experiment, participants were
kobusy [5.1K]

Answer: A

Step-by-step explanation:

Confidence interval for the difference in the two proportions is written as

Difference in sample proportions ± margin of error

Sample proportion, p = x/n

Where x = number of success

n = number of samples

For the first treatment,

x = 35

n1 = 50

p1 = 35/50 = 0.7

For the second treatment,

x = 16

n2 = 40

p2 = 16/40 = 0.4

Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.005 = 0.995

The z score corresponding to the area on the z table is 2.576. Thus, the z score for 99% confidence level is 2.576

Margin of error = 2.576 × √[0.7(1 - 0.7)/50 + 0.4(1 - 0.4)/40]

= 2.576 × 0.10099504938

= 0.26

Confidence interval = 0.7 - 0.4 ± 0.26

= 0.3 ± 0.26

Option A is correct

4 0
4 years ago
Is 27 / 16 a rational number​
dedylja [7]
Yes it is a rational number
6 0
2 years ago
Read 2 more answers
What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)
LuckyWell [14K]

Answer:

Length of the segment QS = 11.76 cm

Step-by-step explanation:

We are given with right angle triangle QRS

Angle S is 80 degree and RS = 2 cm

We need to find out QS

RS is adjacent to angle S, so we use cos formula

Cos (A) = \frac{adjacent}{hypotenuse}

Cos (S) = \frac{RS}{QS}

Plug in the angle and RS

Cos (80) = \frac{2}{QS}

Given cos(80) = 0.17

0.17= \frac{2}{QS}

Multiply by QS on both sides

0.17 * QS = 2

Divide by 0.17 on both sides

QS= 11.76470588

Length of the segment QS = 11.76 cm

6 0
3 years ago
Use the shell method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about th
RSB [31]

Answer:

The volume of the solid is:

\displaystyle\frac{19\pi}{6}

Step-by-step explanation:

See the graph of the region attached.

To find the intersection between the line and the parabola we set the equation equal to each other, and solve that quadratic equation by factorization:

x^2=9-8x\\x^2+8x-9=0\\(x+9)(x-1)=0\\x=-9,x=1

Since the region is the one for x\ge 0 then the intersection we are interested on is x=1 as it can also be seen in the graph.

Then we set the integral using shell method for revolving about the y-axis:

\displaystyle\int_a^b 2\pi\,x\,h(x)\,dx

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so 8x-9-x^2 (since the line is on the top we subtract from it the parabola)

Then the integral becomes:

\displaystyle\int_0^1 2\pi\,x\,(8x-9-x^2)\,dx

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

Now, solving the integral:

Start by factoring the 2\pi and distributing the x:

=\displaystyle2\pi \int_0^19x-8x^2-x^3dx

Then use the basic rule to integrate:

=\displaystyle2\pi \left[\frac{9x^2}{2}-\frac{8x^2}{3}-\frac{x^4}{4}\right|_0^1

Then evaluate the antiderivative in the limits and subtract:

=\displaystyle2\pi\left[\frac{9}{2}-\frac{8}{3}-\frac{1}{4}-0\right]=\frac{19\pi}{6}

So the volume of the solid is \displaystyle\frac{19\pi}{6}

4 0
3 years ago
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