The four consecutive even integers are 20, 22, 24, 26
<em><u>Solution:</u></em>
Let the four consecutive even integers are a , a + 2, a + 4, a + 6
Let "a" be the smallest integer and "a + 6" be the largest integer
To find: the four consecutive even integers
Given that the greatest of four consecutive even integers is 14 less than twice the smallest integer
largest integer = twice the smallest integer - 14
a + 6 = 2(a) - 14
a + 6 = 2a - 14
a - 2a = -14 - 6
-a = -20
a = 20
<em><u>Thus the four consecutive even integers are:</u></em>
a = 20
a + 2 = 20 + 2 = 22
a + 4 = 20 + 4 = 24
a + 6 = 20 + 6 = 26
Thus the four consecutive even integers are 20, 22, 24, 26
Answer:
9+t= 54
Step-by-step explanation:
Answer:
OMG you are so pretty
Step-by-step explanation:
39.99 x .25= 9.999 or 10$ off
39.99-10= 29.99$ in the end (Final Price)
The greatest common factor and factoring by grouping of the following is;
- 3m
- 2a
- 8xy
- 5mn
- 3(r + t)²
- z²(m + n)⁴
<h3>Greatest common factor</h3>
The greatest common factor is the largest positive integer or polynomial that is a divisor of several different numbers. For instance, the greatest common divisor of 66, 30 and 18 is 6.
9m³, 3m², 15m
= 3m
4a², 6a, 2a³
= 2a
16xy³, 24x²y², 8x²y
= 8xy
10m²n², 25mn³, 50m²n
= 5mn
6m(r + t)², 3p(r + t)⁴
= 3(r + t)²
7z²(m + n)⁴, 9z³(m + n)^5
= z²(m + n)⁴
Learn more about greatest common factor:
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