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kolezko [41]
3 years ago
5

An analog-to-digital converter is a device that can be used with a microphone to take in an audio wave (an analog signal). The d

evice then converts the information to a digitized form that can be stored and used by a computer. The image below shows the steps in the digitization process. The question mark in the image represents how the data is stored after it is processed by the analog-to-digital converter.
How is the information from the audio wave stored after it is processed by the analog-to-digital converter?
A.
It is stored as graphs because it was converted to base ten data.
B.
It is stored as a table of ones and twos because it was converted to a radio wave.
C.
It is stored as a series of ones and zeros because it was converted to binary data.
D.
It is stored as images because it was converted to mathematical equations.
Reset
Physics
2 answers:
Stells [14]3 years ago
4 0

Answer:

Answer C <em>It is stored as a series of ones and zeros because it was converted to binary data.</em>

Explanation:

After the Analog to Digital Converter (ADC) the data is stored in a series of numbers encoded in binary mode (combinations of Zeros and Ones).

This agrees with answer labeled as C) in the list of options.

Alla [95]3 years ago
4 0

Answer: C

Explanation: Study Island correct

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When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coeffic
Nuetrik [128]

Answer:

8.1\cdot 10^{-4} C^{-1}

Explanation:

The volumetric expansion of the liquid is given by

\Delta V=\alpha V_0 \Delta T

where

\alpha is the coefficient of volume expansion

V_0 is the initial volume

\Delta T is the change in temperature

For the liquid in this problem,

V_0 = 2.35 m^3\\\Delta T=48.5^{\circ}C\\\Delta V=0.0920 m^3

So we can solve the equation to find \alpha:

\alpha=\frac{\Delta V}{V_0 \Delta T}=\frac{(0.0920 m^3)}{(2.35 m^3)(48.5^{\circ}C)}=8.1\cdot 10^{-4} C^{-1}

7 0
4 years ago
Which of the following should be included in a family communication plan? A. A list of favorite foods and beverages B. A meeting
Ivanshal [37]

Answer:

I believe it's B. A meeting spot for family members

Explanation:

Make copies of your Family Emergency Communication Plan for each member of the household to carry in his or her wallet, backpack, or purse. So they know where to go in case of an emergency!

5 0
3 years ago
Read 2 more answers
Una araña con una masa de 0.26g cuelga verticalmente de uno de sus hilos. El hilo tiene una constante de resorte de 7.1N/m. ¿Cuá
pochemuha

Answer:

Extension, e = 0.0000359 meters

Explanation:

Given the following data;

Mass = 0.26 g

Spring constant = 7.1 N/m

To find the extension of the thread;

Conversion:

1000 grams = 1 kg

0.26 grams = 0.26/1000 = 0.00026 kg

First of all, we would determine the force acting on the spider;

Force = mass * acceleration due to gravity

Force = 0.00026 * 9.8

Force = 0.00255 N

Next, we would determine the extension;

Force = spring constant * extension

Substituting into the equation, we have

0.00255 = 7.1 * extension

Extension, e = 0.00255/7.1

Extension, e = 0.0000359 meters

7 0
3 years ago
Which line represents a stationary object?<br> Position<br> Time
AlladinOne [14]

Answer:

Green one. Red is acc. Blue is Dec and other pink one is constant speed I think

7 0
3 years ago
Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) resp
Sophie [7]

Answer:

(1.9756, -2.1951)

Explanation:

The center of mass equation is: x_{cm} = \frac{m_{1}x_{1}   + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}, where m represents the masses and x represents the position.

In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.

<u>x-values:</u>

<u />x_{cm} = \frac{m_{1}x_{1}   + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}} = \frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12} = \frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41} = \frac{81}{41} = 1.9756

<u>y-values:</u>

<u />y_{cm} = \frac{m_{1}y_{1}   + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}} = \frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12} = \frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41} = \frac{-90}{41} = -2.1951

<u>center of mass:</u>

(1.9756, -2.1951)

6 0
3 years ago
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