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Anna007 [38]
2 years ago
11

Two pebbles are dropped into a pool of water as shown. If a new wave with a

Physics
2 answers:
Zepler [3.9K]2 years ago
7 0

Answer:

C. Constructive interference

Explanation:

Kazeer [188]2 years ago
3 0

Answer:

Constructive interference

Explanation:

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How does Newton's second law of motion can be used to calculate the acceleration of an object?
Alex777 [14]

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

4 0
3 years ago
Analysis: (use a separate sheet of paper)
Zolol [24]

Speed, frequency and wavelength are interconnected to each other.

<h3>What happens to the wavelength if the frequency increases?</h3>

As a wavelength increases in size, its frequency and energy (E) decrease. As the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer.

The wave speed is equal to the product of its frequency and wavelength, which shows the relationship between frequency and wavelength.

So we can conclude that speed, frequency and wavelength are interconnected to each other.

Learn more about frequency here: brainly.com/question/254161

5 0
2 years ago
An Earth satellite is in a circular orbit at an altitude of 500 km.
Dafna1 [17]

Answer:

Speed Unchanged.

Explanation:

As work is defined as a product of force over a distance. If the distance in altitude is constant = 500km, there's 0 change in distance and force, no work would be done by the gravitational force.

Since potential energy of the satellite is unchanged, unless there's additional internal energy source, the kinetic energy would remain unchanged, so would its speed.

8 0
3 years ago
Find the final velocity
Verizon [17]

Answer: v = 4.4 m/s

Explanation:

In the absence of friction, the total mechanical energy will be constant

KE₀ + PE₀ = KE₁ + PE₁

0 + mg(6) = ½mv₁² + mg(5)

½mv₁² = mg(6 - 5)

v = √(2g(1)) = 4.4 m/s

3 0
3 years ago
If a voltmeter has a less than ideal resistance, say 1 MΩ, and is used to measure the voltage across a resistor of a comparable
Naddik [55]

Answer:

As the difference between the resistance of voltmeter and the resistance being measured gets reduced the error in the reading of the voltmeter gets increased.

Explanation:

An ideal voltmeter has infinite parallel resistance and because of this it doesn't draw any current from the circuit of measurement which means it will measure the exact voltage across the elements.

But practically speaking, a real voltmeter doesn't has infinite resistance therefore, all the practical voltmeters face loading effect to some extent.

As the difference between the resistance of voltmeter and the resistance being measured gets reduced the error in the reading of the voltmeter gets increased. This is why we want to have a greater value of voltmeter resistance, ideally infinite so that the corresponding error is minimized.

Lets consider the given scenario,

A voltmeter has 1 MΩ parallel resistance and the resistance of of measuring element is 500 kΩ or 0.5 MΩ

lets suppose the supplied voltage is 1 V.

First lets assume that the voltmeter is ideal and it has infinite resistance, so in this case voltmeter will measure a voltage of 1 V across the 0.5 MΩ resistor.

Now consider the loading effect, when we connect the voltmeter across the 0.5 MΩ resistor they both become parallel so the resistance is

R = (1*0.5)/(1+0.5)

R = 0.33 MΩ

As you can see the voltmeter will see a reduced resistance and the corresponding voltage also reduces because resistance and voltage are directly proportional.

Therefore, it is preferred to have a very high parallel resistance of the voltmeter.

8 0
3 years ago
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