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Sphinxa [80]
3 years ago
8

The graph below shows three different normal distributions. 3 normal distributions are shown. All 3 are at different points on t

he axis. They all have different heights and widths. Which statement must be true? Each distribution has the same mean and the same standard deviation. Each distribution has the same mean and a different standard deviation. Each distribution has a different mean and the same standard deviation. Each distribution has a different mean and a different standard deviation.
Mathematics
2 answers:
tatyana61 [14]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Oduvanchick [21]3 years ago
3 0

Answer:

D: Each distribution has a different mean and a different standard deviation.

Step-by-step explanation:

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Lapatulllka [165]
I think it’s A.6.3
Sorry if I’m wrong but I’m pretty sure it’s that.
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3 years ago
Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p
Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0
3 years ago
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adell [148]

Answer:

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Step-by-step explanation:

I am not very sure but this would be the answer.

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3 years ago
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Fynjy0 [20]
No, 1 and 3/9 can be simplified to 1 and 1/3
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Find f (0) if f(t) = t2 – 2t – 5.
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0(2)- 2(0)- 5 =
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