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skad [1K]
3 years ago
13

Solve x squared = 10

Mathematics
1 answer:
balu736 [363]3 years ago
5 0

Answer:

=3.162

Step-by-step explanation:

x2  

= −0 + √ 02 − 4×1×(−10)  

2×1

= 0 + 2 × √ 10  

2

= 3.162

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5(x+1)=20<br><br> What is is the answer?
Ilia_Sergeevich [38]

Steps to solve:

5(x + 1) = 20

~Distributive property

5x + 5 = 20

~Subtract 5 to both sides

5x + 5 - 5 = 20 - 5

~Simplify

5x = 15

~Divide 5 to both sides

5x/5 = 15/5

~Simplify

x = 3

Best of Luck!

3 0
3 years ago
Read 2 more answers
3. Given the directed line segment AB, with endpoints A20, 6) and B(-16, 50), find the point Q
garri49 [273]

The point Q that partitions the line segment is Q(2,28)

Given that the directed line segment AB, with endpoints A(20, 6) and B(-16, 50) and divide the segment into a 1:1 ratio.

A line segment is a part of a line bounded by two distinct endpoints and containing all the points of the line segment between its endpoints.

We will find the point Q by using the section formula that is

Q(x,y)=((mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n))

The given ratio is m:n=1:1 and the points (x₁,y₁)=(20,6) and (x₂,y₂)=(-16,50).

Firstly, we will find the point Q for x-axis, we get

Q(x)=(mx₂+nx₁)/(m+n)

Q(x)=(1×(-16)+1×20)/(1+1)

Q(x)=(-16+20)/2

Q(x)=4/2

Q(x)=2

Now, we will find the point Q for y-axis, we get

Q(y)=(my₂+ny₁)/(m+n)

Q(y)=(1×50+1×6)/(1+1)

Q(y)=(50+6)/2

Q(y)=56/2

Q(y)=28

The point Q that partitions the line segment is Q(x,y)=(2,28)

Hence, point Q partitions this segment into a 1:1 ratio with directed line segment AB, with endpoints A(20, 6) and B(-16, 50) is Q(2,28).

Learn more about the line segment from here brainly.com/question/9034900

#SPJ9

8 0
2 years ago
How many solutions are there in the given equation?<br> y = 2x² + 6x + 4
tigry1 [53]

Step-by-step explanation:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

2

+

6

+

4

=

0

2x^{2}+6x+4=0

2x2+6x+4=0

=

2

a={\color{#c92786}{2}}

a=2

=

6

b={\color{#e8710a}{6}}

b=6

=

4

c={\color{#129eaf}{4}}

c=4

=

−

6

±

6

2

−

4

⋅

2

⋅

4

√

2

⋅

2

x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{2}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{2}}}

x=2⋅2−6±62−4⋅2⋅4

brainliest and follow and thanks

8 0
3 years ago
Write an equation for the parabola whose vertex is at (4, 12) and which passes through (5, 21)
laiz [17]

Answer:

y - 12 = 9(x - 4)

Step-by-step explanation:

The vertex (h, k) is (4, 12) and the point (5, 21) is on the graph.  Assuming that this is a vertical parabola, opening up (because the coordinate 21 is greater than the coordinate 12), we insert the knowns into  y - k = a(x - h)^2, obtaining

21 - 12 = a(5 - 4), or  9 = a.  With a known, we can write the desired equation:

y - 12 = 9(x - 4)

8 0
3 years ago
the 8th grade class planned a trip to kings dominion and 120 students went. Ten students rode with their parents. The rest rode
Papessa [141]

120-10=110/2=55 students per bus

5 0
4 years ago
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