Someone help heree plss

What fraction is the greatest in this row? 12/4, 4/4, 2 2 / 4, 1/4. also 2 2 /4 is a mixed number

kakasveta [241]

Answer:

12/4

Step-by-step explanation:

4/4 is 1

1/4 is well 1/4

2 2/4 is 2 1/2

12/4 is 3

the greatest fraction is 3

4 0

3 years ago

Read 2 more answers

Find the general solution of (2x² + y)dx + (x²y - x)dy = 0

dmitriy555 [2]

Multiply the original DE by xy:

xy2(1+x2y4+1−−−−−−−√)dx+2x2ydy=0(1)

Let v=xy2, so that dv=y2dx+2xydy. Then (1) becomes

x(y2dx+2xydy)+xy2x2y4+1−−−−−−−√dxxdv+vv2+1−−−−−√dx=0=0

This final equation is easily recognized as separable:

dxxln|x|+CKxvKx2y2−1K2x4y4−2Kx2y2y2=−dvvv2+1−−−−−√=ln∣∣∣v2+1−−−−−√+1v∣∣∣=v2+1−−−−−√+1=x2y4+1−−−−−−−√=x2y4=2KK2x2−1integrate both sides

8 0

3 years ago

One study found that the number of interest groups increased by what percentage between 1959 and 1995?

FrozenT [24]

Answer:

Percentage change in interest groups between 1959 (500) & 1995 (600) = 20%

Step-by-step explanation:

Percentage change = <u>Change ie (New - Old) </u> x 100

Old value

Suppose -

Number of interest groups in 1959 = 500

Number of interest groups in 1995 = 600

Percentage change = [ (600 - 500) / 500 ] x 100

( 100 / 500 ) x 100 = 20%

6 0

3 years ago

Help pls I’ll give 50 points ! If right math ppl

Georgia [21]

$f(x)=-3x$

Substitute x = 5 in the equation.

$f(5)=-3(5)\\f(5)=-15$

Therefore, the answer is -15 or last choice when x = 5.

3 0

3 years ago

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An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .

We have to find M.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 2.81\sqrt{\frac{0.12*0.88}{5615}}$

$M = 0.012$

7 0

3 years ago