Someone help heree plss

Mathematics

1 answer:

Novay_Z [31]3 years ago

3 0

Answer:

a c and g

Step-by-step explanation:

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What is the sum of 2 1/3, 3 5/6 and 6 2/3

Andreas93 [3]

2 1/3+ 3 5/6+ 6 2/3
= 7/3+ 23/6+ 20/3
= 14/6+ 23/6+ 40/6
= 77/6
= 12 5/6

The final answer is 12 5/6~

5 0

3 years ago

Square root of 81 minus square root of negative 48 answer in a + bi form

galina1969 [7]

Answer:

9-6.92820323i Nothing else can be done.

Step-by-step explanation:

-48 is not a perfect square but 81 is a square. When you try to square -48 it comes to be 6.92820323i.

4 0

3 years ago

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>