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2 years ago

HELP!can somebody give me the answer then explain how they did and if you cheated tell me how you cheated lol

Mathematics

1 answer:

amm18122 years ago

7 0

Area is lengthxwidth
So just divide area by the given width
Gives you 99 m

Perimeter for a rectangle is 2l+2w
If one length is 94, 94x2 = 188
Subtract that from the 354 = 166
Divide by two because it’s 2w
83 cm

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Answer this urgently, please!!!!

Inessa05 [86]

Answer:

exact form: 55/256

decimal form: 0.21484375

4 0

2 years ago

Write an equation for the nth term of<br> the arithmetic sequence: <br> 15,28,41 ....

11111nata11111 [884]

Answer:

The equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

Step-by-step explanation:

We need to write an equation for the nth term of the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: $a_n=a_1+(n-1)d$

Where $a_n$ is the nth term, $a_1$ is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

$a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13$

So, the common difference d is 13

Now, equation for nth term will be:

$a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2$

So, the equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

where n=1,2,3..

4 0

2 years ago

The curves r1(t) = 2t, t2, t4 and r2(t) = sin t, sin 5t, 2t intersect at the origin. Find their angle of intersection, θ, correc

masya89 [10]

Answer:

Therefore the angle of intersection is $\theta =79.48^\circ$

Step-by-step explanation:

Angle at the intersection point of two carve is the angle of the tangents at that point.

Given,

$r_1(t)=(2t,t^2,t^4)$

and $r_2(t)=(sin t , sin5t, 2t)$

To find the tangent of a carve , we have to differentiate the carve.

$r'_1(t)=(2,2t,4t^3)$

The tangent at (0,0,0) is [ since the intersection point is (0,0,0)]

$r'_1(0)=(2,0,0)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{2^2+0^2+0^2} =2$

Again,

$r'_2(t)=(cos t ,5 cos5t, 2)$

The tangent at (0,0,0) is

$r'_2(0)=(1 ,5, 2)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{1^2+5^2+2^2} =\sqrt{30}$

If θ is angle between tangent, then

$cos \theta =\frac{r'_1(0).r'_2(0)}{|r'_1(0)|.|r'_2(0)|}$

$\Rightarrow cos \theta =\frac{(2,0,0).(1,5,2)}{2.\sqrt{30} }$

$\Rightarrow cos \theta =\frac{2}{2\sqrt{30} }$

$\Rightarrow cos \theta =\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =cos^{-1}\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =79.48^\circ$

Therefore the angle of intersection is $\theta =79.48^\circ$ .

8 0

2 years ago

Use the table to find the COORDINATES of the image

Natasha_Volkova [10]

Answer:

Q = ( -3 , 6 ) .... R = ( -1 , 8 ) ...... S = ( -5 , 7 )

Step-by-step explanation:

Q = ( 1 + ( -4 ) , 4 + 2 ) = ( -3 , 6 )

R = ( 3 + ( -4 ) , 6 + 2 ) = ( -1 , 8 )

S = ( -1 + ( -4 ) , 5 + 2 ) = ( -5 , 7 )

8 0

2 years ago

35 POINTS! PLEASE HELP MEEE!!! HURRY PLEASE IM RUNNING OUT OF TIME!!!!!!!!!!!!!!!!!

lesantik [10]

Answer:

<h2>CYLINDER</h2>

Surface Area = 471.2 cm^2

<h2>TRIANGULAR PRISM</h2>

Surface Area = 60.75 m^2

Step-by-step explanation:

<h2>CYLINDER</h2>

The surface area formula for a cylinder is π x diameter x (diameter / 2 + height), where (diameter / 2) is the radius of the base (d = 2 x r), so another way to write it is π x radius x 2 x (radius + height). ( π =3.14 )

FORMULA:

π x 5 x 2 x 15

WORK:

π x 5 = 15.7

15.7 x 2 = 31.4

31.4 x 15 = 471

<h2>TRIANGULAR PRISM</h2>

The surface area formula for a triangular prism is 2 * (height x base / 2) + length x width1 + length x width2 + length x base.

FORMULA:

2 x (2.5 x 1.5/2) + (6 x 4) + (6 x 4) + (6 x 1.5)

WORK:

(2.5 x 1.5) = 3.75/2 = 1.875

1.875 x 2 = 3.75

(6 x 4) = 24

(6 x 1.5) = 9

3.75 + 24 + 24 + 9 = 60.75

5 0

3 years ago

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