1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pantera1 [17]
3 years ago
10

How does Newton's first law affect human motions answer

Physics
1 answer:
vazorg [7]3 years ago
8 0
The First Law states, "A body at rest will remain at rest, and a body in motion will remain in motion unless it is acted upon by an external force." This simply means that things cannot start, stop or change direction all by themselves. It requires some force acting on them from the outside to cause such a change. Hope this helps! Mark brainly please!
You might be interested in
Please help...........................
Marianna [84]
Hi!

Neutrons are neutral, which means they don't exactly have an electrical charge. It's because of this neutral charge that it is represented with a '0'. 

On the other hand, protons and electrons <em>do </em>have electrical charges. Electrons flow around the outside of the nucleus, with a negative charge.

Protons are stored in the nucleus with the neutrons, holding a positive charge.

Hopefully, this helps! =)
6 0
4 years ago
Read 2 more answers
A force of 44 N will stretch a rubber band 88 cm ​(0.080.08 ​m). Assuming that​ Hooke's law​ applies, how far will aa 11​-N forc
Setler79 [48]

Answer:

<em>The rubber band will be stretched 0.02 m.</em>

<em>The work done in stretching is 0.11 J.</em>

Explanation:

Force 1 = 44 N

extension of rubber band = 0.080 m

Force 2 = 11 N

extension = ?

According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.

F = ke

where k = constant of elasticity

e = extension of the material

F = force applied.

For the first case,

44 = 0.080K

K = 44/0.080 = 550 N/m

For the second situation involving the same rubber band

Force = 11 N

e = 550 N/m

11 = 550e

extension e = 11/550 = <em>0.02 m</em>

<em>The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch</em>. This is in line with energy conservation.

potential energy stored = \frac{1}{2}ke^{2}

==> \frac{1}{2}* 550* 0.02^{2} = <em>0.11 J</em>

3 0
3 years ago
Physics<br><br><br><br><br><br><br> is my answer correct?
Digiron [165]

Explanation:

zero..................

6 0
3 years ago
Read 2 more answers
Write about Geothermal energy????????????
svlad2 [7]
Energy Produced by water and heatfrom the inner core of the earth of the earth
8 0
3 years ago
Acceleration is the magnitude of average velocity true or false
Talja [164]

Answer:

False

Explanation:

8 0
3 years ago
Other questions:
  • Which statements about inertia and centripetal force are correct? Check all that apply. Inertia is always present. Inertia cause
    10·2 answers
  • Un resorte se monta horizontalmente con su extremo izquierdo fijo. Conectando una balanza de
    11·1 answer
  • Which type of plate boundary led yo the creation of the himalayan mountains,the Highest in the world, near India?
    9·1 answer
  • The headlights are shining on a truck travelling at 100 km/h. The speed of the light from the headlights relative to the road wi
    10·2 answers
  • You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then lo
    11·1 answer
  • How does increasing the number of resistors in a parallel branch change the total resistance of the system?
    5·1 answer
  • A food scientist often develops new __________________________.
    5·2 answers
  • In The unit of power is a<br>derived unite<br>The unit of power is<br>a derived unit be con<br>CAY​
    12·1 answer
  • How much force is needed to pull a spring with a spring constant of 20 N/m a distance of<br> 25 m?
    5·1 answer
  • Question 20 (4 points)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!