I think the situation is modeled by the scenario in the attached image. Some specific values seem to be missing (like the height of door
)...
The door forms a right triangles that satisfies
![\tan\theta=\dfrac ab\implies\sec^2\theta\dfrac{\mathrm d\theta}{\mathrm dt}=\dfrac{b\frac{\mathrm da}{\mathrm dt}-a\frac{\mathrm db}{\mathrm dt}}{b^2}](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%5Cdfrac%20ab%5Cimplies%5Csec%5E2%5Ctheta%5Cdfrac%7B%5Cmathrm%20d%5Ctheta%7D%7B%5Cmathrm%20dt%7D%3D%5Cdfrac%7Bb%5Cfrac%7B%5Cmathrm%20da%7D%7B%5Cmathrm%20dt%7D-a%5Cfrac%7B%5Cmathrm%20db%7D%7B%5Cmathrm%20dt%7D%7D%7Bb%5E2%7D)
We also have
![\tan\theta=\dfrac ab\implies\cos\theta=\dfrac bd](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%5Cdfrac%20ab%5Cimplies%5Ccos%5Ctheta%3D%5Cdfrac%20bd)
so if you happen to know the height of the door, you can solve for
and
.
is fixed, so
![a^2+b^2=d^2\implies2a\dfrac{\mathrm da}{\mathrm dt}+2b\dfrac{\mathrm db}{\mathrm dt}=0\implies\dfrac{\mathrm da}{\mathrm dt}=-\dfrac ba\dfrac{\mathrm db}{\mathrm dt}](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dd%5E2%5Cimplies2a%5Cdfrac%7B%5Cmathrm%20da%7D%7B%5Cmathrm%20dt%7D%2B2b%5Cdfrac%7B%5Cmathrm%20db%7D%7B%5Cmathrm%20dt%7D%3D0%5Cimplies%5Cdfrac%7B%5Cmathrm%20da%7D%7B%5Cmathrm%20dt%7D%3D-%5Cdfrac%20ba%5Cdfrac%7B%5Cmathrm%20db%7D%7B%5Cmathrm%20dt%7D)
We can solve for the angular velocity
:
![\dfrac{\mathrm d\theta}{\mathrm dt}=\cos^2\theta\dfrac{b\left(-\frac ba\frac{\mathrm db}{\mathrm dt}\right)-a\frac{\mathrm db}{\mathrm dt}}{b^2}=-\dfrac1a\dfrac{\mathrm db}{\mathrm dt}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5Ctheta%7D%7B%5Cmathrm%20dt%7D%3D%5Ccos%5E2%5Ctheta%5Cdfrac%7Bb%5Cleft%28-%5Cfrac%20ba%5Cfrac%7B%5Cmathrm%20db%7D%7B%5Cmathrm%20dt%7D%5Cright%29-a%5Cfrac%7B%5Cmathrm%20db%7D%7B%5Cmathrm%20dt%7D%7D%7Bb%5E2%7D%3D-%5Cdfrac1a%5Cdfrac%7B%5Cmathrm%20db%7D%7B%5Cmathrm%20dt%7D)
At the point when
and
ft/s, we get
![\dfrac{\mathrm d\theta}{\mathrm dt}=-\dfrac{1.8}a\dfrac{\rm deg}{\rm s}=-\dfrac{1.8}{d\sin40^\circ}\dfrac{\rm deg}{\rm s}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5Ctheta%7D%7B%5Cmathrm%20dt%7D%3D-%5Cdfrac%7B1.8%7Da%5Cdfrac%7B%5Crm%20deg%7D%7B%5Crm%20s%7D%3D-%5Cdfrac%7B1.8%7D%7Bd%5Csin40%5E%5Ccirc%7D%5Cdfrac%7B%5Crm%20deg%7D%7B%5Crm%20s%7D)
Can you show the diagram please
Answer:
Adsorption
Explanation:
Sidewalk cooking of egg is very popular in America. In summer people release fireworks in night sky and cook egg on the concrete sidewalk to check the level of temperature. When sunlight fall on the sidewalk most of the light is reflected back but some darker material adsorbs some photon, and when these photons are transferred to egg molecules it causes vibration among them and produce heat and cook egg.
I'm pretty sure that there should be an options to choose. Anyway, I've seen this question before and I know that this is an example of <span>the phi phenomenon.</span>