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Burka [1]
3 years ago
5

Which best describes the error in finding the surface area of the cylinder? I aM CoNfuSiOn

Mathematics
2 answers:
Kazeer [188]3 years ago
7 0

The area of only one base was added. The first term should have a factor of 2.

xxMikexx [17]3 years ago
6 0
The mistake is the first equation where S = blah blah. The equation or the formula to find the surface area of the cylinder is wrong.

Hope this helps if so mark me the brainiest!!
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What's the correct formula for this function? ​
Reptile [31]

Answer:

Option C. y = -2x + 3

Step-by-step explanation:

When we look at this function we see that it has a negative slope and the y-intercept is equal to (0,3).  From this we know that the function we are looking for will be looking like...

y = mx + 3

And as I said earlier since the slope is negative, the only right option is this case will be Option C

8 0
3 years ago
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What is the the answer​
timofeeve [1]

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7 0
2 years ago
Idk the answer to this question please help me
erica [24]
2/3 x 42/3
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7 0
3 years ago
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Pavlova-9 [17]

Answer:

43:22

Step-by-step explanation:

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86:44

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4 0
2 years ago
Verify:<br>cos(2A)=(cotA-tanA)/cscAsecA​
kolbaska11 [484]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

cot A = \frac{cosA}{sinA}, tanA = \frac{sinA}{cosA}, cscA  = \frac{1}{sinA}, secA = \frac{1}{cosA}

Consider the right side

\frac{cotA-tanA}{cscAsecA}

= \frac{\frac{cosA}{sinA}-\frac{sinA}{cosA}  }{\frac{1}{sinA}.\frac{1}{cosA}  }

= \frac{\frac{cos^2A-sin^2A}{sinAcosA} }{\frac{1}{sinAcosA} }

= \frac{cos^2A-sin^2A}{sinAcosA} × sinAcosA ( cancel sinAcosA )

= cos²A - sin²A

= cos2A

= left side ⇒ verified

5 0
3 years ago
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