6.
![y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=y%5E2%5Csqrt%5B8%5D%7B8%7D)
Step-by-step explanation:
![\sqrt[8]{8*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B8%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%7D)
Since there are eight y's in two groups we can take them out which turns into
:)
3.
We need the total count of persons = 10+12+12+15 = 49 persons
We need the count of the target group, female or teaching assistants
= (10+12) professors + 12 male teaching assistants
= 22+12
= 34 persons
Assuming equal probability of choosing anyone from the 30 persons, the
probability of choosing a professor or a male
= 34/49
(For probability calculations, try to keep a fraction for as long as you can, because fractions are exact. Decimal are frequently approximate, for example in this case, 34/49=0.693877551020...... = 0.694 approximately)
Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
One side of the rectangle is x=2, the other side is 2x-5
Add up all the four sides: (x+2) +(x+2)+(2x-5)+(2x-5)=54
6x-6=54
x=10
#3: suppose the first integer is x, then the second one is x+2
x(x+2)=255
x^2 +2x -255 =0
factor the quadratic equation: (x+17)(x-15)=0
x=-17, which is impossible, or x=15
so the two positive integers are 15 and 17
