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VikaD [51]
3 years ago
6

Which expression is equivalent to -8(x-4)-1/4(12x-8)

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0

Answer:

Step-by-step explanation:

-8(x-4)-1/4(12x-8)=

=-8x+32-1/4(4)(3x-2)=

=-8x+32-3x+2=-11x+34

-11x=-34

x=34/11=3 1/11

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Jlenok [28]

Answer:

a) Translate the graph of f(x) down 3 units.

b) (8,-1) is a point on the graph of g(x)

Step-by-step explanation:

The transformations that subtract a constant number of units from the functional expression f(x) are transformations that lower the graph of the function in those many units,

Therefore they correspond to a translation of the original graph down the number of units involved.

In this case, the number of units involved is "3" (due to the "-3" added to the expression for f(x). So he correct answer for the first part is: Translate the graph of f(x) down 3 units.

For the second part, one has to try each of the coordinate pairs given in the new function g(x) to see which one results in a true statement:

1) Testing (-8,-1) by checking if replacing x with the value "-8" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(-8)=\sqrt[3]{-8} -3\\g(-8)=-2-3\\g(-8)=-5

so this is NOT a point on the graph of g(x).

2) Testing (-1,-2) by checking if replacing x with the value "-1" renders "-2" for the y-value: g(x)=\sqrt[3]{x} -3\\g(-1)=\sqrt[3]{-1} -3\\g(-1)=-1-3\\g(-1)=-4

so this is NOT a point on the graph of g(x).

3) Testing (2,-1) by checking if replacing x with the value "2" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(2)=\sqrt[3]{2} -3\\

the cubic root of 2 is not a rational number, because 2 is not a perfect cube, so the expression cannot be reduced, so this is NOT a point on the graph of g(x).

4) Testing (8,-1) by checking if replacing x with the value "8" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(8)=\sqrt[3]{8} -3\\g(8)=2-3\\g(8)=-1

Therefore this pair (8,-1) IS a point on the graph of g(x).

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I think this is right maybe

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