Answer:
0.025
Step-by-step explanation:
Given that the arrival time of a professor to her office is uniformly distributed in the interval between 8 and 9 A.M.
If the professor did not arrive till 8.20 he will arrive between 8.21 and 8.40
Hence probability for arriving after 8.20 is 1/40
Prob he arrives at exactly 8.21 is 1/60
To find the probability that professor will arrive in the next minute given that she has not arrived by 8: 20.
= Prob that the professor arrives at 8.21/Prob he has not arrived by 8.20
This is conditional probability and hence
= 
Answer:
Correct answer is B. (second Choice)
Step-by-step explanation:
<span>The answer is true
Let's imagine that we have the following function function:
</span>

<span>We have to:
Independent variable: x
Dependent variable: y
For x = -1:
</span>

<span> For x = 1:
</span>

<span> We observe that the independent variable can only obtain one result.
Answer:
True</span>
Answer:
2
Step-by-step explanation:
I think :)
To be honest I am not sure but maybe 32 because that is half or 96 but I was never really good with scales.