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alexandr1967 [171]
2 years ago
14

the baltimore stockbrocker One day you receive an unsolicited newsletter from a stockbroker in Baltimore, containing a tips that

a certain stock is due for a big rise. A week passes, and just as the Baltimore Stockbroker predicted, the stock goes up. The next week, you get a new edition of the newsletter, and the time, the tip is about a stock whose pnce the broker thinks is going to fall. And indeed the stock criters. Ten weeks go by each one bringing a new issue of the mysterious newsletter with a new prediction and each time, the prediction comes true. How is possible. There is a logical way this could happen, this is one of the world's most famous ways of defrauding people. What is the probability of this occurring for you(one person)?
Mathematics
1 answer:
Mnenie [13.5K]2 years ago
7 0
The person would be able to get a week pass
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There are 16 colored pencils and 8 colored pencils will fit in a box. How many boxes will the 16 pencils fill?
Gekata [30.6K]

Given:

Total number of colored pencils = 16

Colored pencils fit in a box = 8

To find:

The number of boxed that will fit the 16 pencils.

Solution:

According to the question 8 colored pencils will fit in a box. So, we have

8 pencils = 1 box

Multiply both sides by 2.

2×8 pencils = 2×1 box

16 pencils = 2 box

Therefore, 2 boxes are required to fit the 16 colored pencils.

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2 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

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