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Alina [70]
3 years ago
11

a 3.5 kg mass has an initial velocity of 4.0 m/s. How much force is required to increase the velocity of the mass to 8.0 m/s in

3.0 seconds?
Physics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

<em>4.67 N of force are required</em>

Explanation:

The second Newton's law states the net force exerted on a body of mass m that has an acceleration a, is given by:

F=m.a

On the other hand, the kinematics equations relate the acceleration with the change of speed over time, expressed as:

\displaystyle a=\frac{v_f-v_o}{t}

We are given the initial speed of vo=4 m/s on a mass of m=3.5 Kg, the final speed of vf=8 m/s which took t=3 seconds.

The acceleration is:

\displaystyle a=\frac{8-4}{3}=1.33

a=1.33\ m/s^2

Thus, the force is:

F=3.5\ Kg\cdot 1.33\ m/s^2

F=4.67\ N

4.67 N of force are required

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Answer:

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Explanation:

From Pascal's law, the pressure at the bottom of the container is the pressure from the atmosphere and the columns of water and olive , therefore

Pressure at the bottom = Pressure at the surface of the liquid ( atmospheric pressure) + pressure of the column of water + pressure of the column of olive oil

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density of olive oil was taken from internet sources ( we can check that is lower than the one of water, and thus it floats )

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