3 years ago

In terms of substances explain why evaporation of water is a physical change and not a chemical change

1 answer:

8 0

Physical change is changing physically it eg appearance while chemical change is the molecular bonds water is always defined as H2O and not change chemically. Hope this answers your question.

You might be interested in

Why don’t you fall through the floor

AfilCa [17]

Because it’s made out of wood

7 0

3 years ago

Read 2 more answers

A runner wants to run 12.0 km . Her running pace is 8.2 mi/hr . How many minutes must she run? Express your answer using two sig

Hunter-Best [27]

Answer:

53 minutes

Explanation:

To solve this problem, we need to use common proportions to convert.

= 11.7km * 1mi/1.61km * 1hr/8.2mi * 60min/hr

≈ 53 minutes

Best of LUck!

5 0

3 years ago

Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiment

Drupady [299]

Answer:

$u_K=0.862$

Explanation:

The force of friction between the quails feet and the ground is:

$F=m*a$

$F_K=m*a$

$F_K=u_k*m*g$

$u_K*m*g=m*a_c$

$u_K*g=a$

$u_K=\frac{a_c}{g}$

$a_c=\frac{v^2}{r}$

So the coefficient of static is solve

$u_K=\frac{\frac{v^2}{r}}{g}$

$u_K=\frac{v^2}{r*g}=\frac{(2.6m/s)^2}{0.80m*9.8m/s^2}$

$u_K=0.862$

4 0

3 years ago

10. A man throws a water balloon down off the edge of a building. If he wants the water

stepladder [879]

Answer:

intinal speed should be 10

Explanation:

v = v0 + at

30 = v0 +10.2

then v0= 10

5 0

2 years ago

Consider a space shuttle which has a mass of about 1.0 x 105 kg and circles the Earth at an altitude of about 200.0 km. Calculat

svetlana [45]

Answer:

1.6675×10^-16N

Explanation:

The force of gravity that the space shuttle experiences is expressed as;

g = GM/r²

G is the gravitational constant

M is the mass = 1.0 x 10^5 kg

r is the altitude = 200km = 200,000m

Substitute into the formula

g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²

g = 6.67×10^-6/4×10^10

g = 1.6675×10^{-6-10}

g = 1.6675×10^-16N

Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N

6 0

2 years ago