Answer:
hope that it helps
Explanation:
A. can accurately recall memories of early childhood and infancy.
Answer:
False
Explanation:
Paleobotany is the study of fossil plants.
Answer:
A = 0.325 Bq
Explanation:
given,
half life of ¹⁴C = 5730 years
fixed fraction 1.30 × 10⁻¹² of ¹²C
half life = 5730 years
T_{1/2} = 5730 x 365 x 24 x 60 x 60
= 1.807 x 10¹¹ s
radioactive decay constant
λ =
λ =
λ = 3.835 x 10⁻¹² /s
number of atom
mass m = 1.30 g
n = 6.524 x 10²²
Number of ¹⁴C atoms in 1.3 g of sample N ' =
= 1.30 × 10⁻¹² x 6.524 x 10²²
= 8.482 x 10¹⁰
Required activity, A = λ N
A = 3.835 x 10⁻¹² x 8.482 x 10¹⁰
A = 0.325 Bq
Answer:
A. Zero
Explanation:
Given data,
The charge of the test charge, q = 1 C
The distance moved against the field of intensity, r = 30 cm
= 0.3 m
The electric field, E = 50 N/C
The formula for energy stored in the charge is,
V = k q/r
Where,
= 9 x 10⁹ Nm²C⁻²
The charge is moved from the potential V₁ to V₂ at 30 cm
Substituting the given values in the above equation
V₁ = 9 x 10⁹ x 30 / 0.3
= 1.5 x 10¹² J
And,
V₂ = 1.5 x 10¹² J
The energy stored in it is,
W = V₂ - V₁
= 0
Hence, the energy stored in the charge is, W = 0