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4 years ago

8

What is the value of tan x ?

1 answer:

Ronch [10]4 years ago

8 0

Tangent is opposite over adjacent, so 4/3

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PLEASEEEE HELPP MEE WITHHH NUMBERRR 10!!!!!!<br> PLEASSEEE AND I NEED A GREAT EXPLANATIOn

Blababa [14]

Answer:

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Step-by-step explanation:

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3 years ago

Evaluate -|-8-2|<br> -6<br> -10<br> 10

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4 years ago

He total variance is $35000 f. the total materials variance is $14000 f. the total labor variance is twice the total overhead va

TiliK225 [7]

Assume that the total overhead variance is x
We are given that the total labor variance is twice the total overhead variance. This means that, the total labor variance is 2x

Total variance can be calculated as follows:
Total variance = Total materials variance + Total overhead variance
+ Total labor variance

We have:
Total variance = $35000
Total materials variance = $14000
Total overhead variance = x
Total labor variance = 2x

Substitute in the equation and solve for x as follows:
35000 = 14000 + x + 2x
35000 - 14000 = 3x
21000 = 3x
x = 21000/3
x = 7000

Based on the above calculations:
Total overhead variance = x = $7000
Total labor variance = 2x = 2*7000 = $14000

4 0

3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

Help plz anybody ????????????

Kobotan [32]

Answer: 18 square ft.

Step-by-step explanation:

Surface area is length*width. 1*1= 1*6= 6

since there are three cubes, it is 6*3= 18 square ft total.

4 0

3 years ago