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Anit [1.1K]
4 years ago
8

What is the value of tan x ?

Mathematics
1 answer:
Ronch [10]4 years ago
8 0
Tangent is opposite over adjacent, so 4/3
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In a bag with 8 red, 2 white, 4 yellow, and 7 green marbles, what is the ratio of GREEN to WHITE marbles? Write your answer in c
LenKa [72]
The ratio between green to white 7:2
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3 years ago
The probability that Shelly will go to a movie (event A) on Friday is 0.78, and the probability that Danielle will go to a movie
seropon [69]
The right answer for the question that is being asked and shown above is that: "c. Events A and B are dependent because P(A|B) = P(A) x P(B)."<span>The probability that Shelly will go to a movie, given that Danielle goes to a movie, is 0.87. </span>
5 0
4 years ago
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
First answer get brainliest
dezoksy [38]

A

-1/4

1/3 times -3/4

-3x1=-3

4x3=12

-3/12=-1/4

6 0
3 years ago
The expression (6x+18) represents the area of the model below. Which expression could NOT represent the dimensions of the model?
garri49 [273]

Answer:

A) 3(x+6)

Step-by-step explanation:

Given,

The area of the model = (6x+18)

If the dimensions of the model are, x unit × y unit,

Then,

xy = 6x + 18

If x = 3, y = x + 6

3(x+6) = 3x + 18 ( by distributive property )

∴ Option A doesn't represent the dimensions of the model,

If x = 6, y = x + 3

6(x+3) = 6x + 18

∴ Option B represents the dimensions of the model,

If x = 0.5, y = 12x+36

0.5(12x+36) = 6x + 18

∴ Option C represents the dimensions of the model,

If x = 0.25, y = 24x + 72

0.25(24x+72) = 6x+18

∴ Option D represents the dimensions of the model,

8 0
3 years ago
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