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goblinko [34]
3 years ago
11

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Mathematics
1 answer:
rusak2 [61]3 years ago
7 0
Hello there!

The correct answers are -10, -12, -14, -16, -18, -20, -22, -24, -26, -28.


Hope This Helps You!
Good Luck :)

(P.S, sorry for the late answer, i got a little busy)
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Use the quadratic formula to solve x2+7x+3. Show all of your work. Then describe the solution.
Mariana [72]

Answer:

Step-by-step explanation:

The coefficients of the quadratic x^2 + 7x + 3 are a = 1, b = 7 and c = 3.

The discriminant is b^2 - 4ac, or 49 - 4(1)(3), or 49-12, or 37.

Because the discriminant is positive, we know that this quadratic equation has two real, different solutions.

      -7 ± √37

x = ---------------   =>   x = (-7 + √37)/2  and  x = (-7 - √37)/2

             2

In words:  This quadratic equation has two real, unequal solutions involving the radicand 37.

7 0
3 years ago
Two complex numbers are represented by c + di and , where c, d, e, and f are positive real numbers. In what two quadrants may th
myrzilka [38]

Answer: In quadrant 1 or quadrant 2.

Step-by-step explanation:

We have the numbers:

x = c + di

y = e + fi

where c, d, e and f are real positive numbers.

the product of these numbers is:

x*y = (c + di)*(e + fi) = c*e + c*fi + d*ei ´+d*f*i^2

x*y = c*e - d*f + (c*f + d*e)i

where I used that i^2 = -1

knowing that c,f, d and e are positive numbers, then the imaginary part of the product must be always positive.

For the real part, we have c*e - d*f, that can be positive o negative depending on the values of c, e, d, and f.

So we have that the product must lie always in one of the upper two quadrants, quadrant 1 or quadrant 2 because the imaginary part is always positive and the real part can be positive or negative.

6 0
3 years ago
17. A hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm. Find
Pavlova-9 [17]

Answer:

r = 3.74cm

Step-by-step explanation:

Given

Hemisphere

Radius = 7cm

Cone

Height = 49m

Required

Determine the radius of the cone

First, we calculate the volume (V1) of the hemisphere.

V_1 = \frac{2}{3}\pi r^3

Substitute 7 for r

V_1 = \frac{2}{3}\pi * 7^3

V_1 = \frac{2}{3}\pi * 343

V_1 = \frac{686}{3}\pi

Volume (V2) of a cone is:

V_2 = \frac{1}{3}\pi r^2h

Because the lead is cast into a cone, then they have the same volume.

So, we have:

\frac{686}{3}\pi = \frac{1}{3}\pi r^2h

686 =  r^2h

Substitute 49 for h

686 =  r^2 * 49

Divide both sides by 49

r^2 = \frac{686}{49}

r^2 = 14

r = \sqrt{14

r = 3.74cm

<em>Hence, the radius of the cone is 3.74cm</em>

5 0
3 years ago
What is the surface area of a triangular pyramid if each face has an area of 80 m2?
TiliK225 [7]
There are 4 sides in a triangular pyramid. So just multiply 80m2 by 4
80×4=24
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3 years ago
Find the probability that the next 1000 cars purchased in your city will all be the color blue
Stolb23 [73]
D
because it is the only reasonable answer
7 0
3 years ago
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