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Sidana [21]
2 years ago
13

X - 3/2 = 3. Please show your work. Will mark BRAINLIEST

Mathematics
1 answer:
BARSIC [14]2 years ago
4 0

\huge\text{Hey there!}

\mathsf{x-\dfrac{3}{2}=3}

\large\textsf{You have to SIMPLIFY the SIDES of   The  given EQUATION}

\mathsf{x + (-\dfrac{3}{2}) = 3}

\large\textsf{ADD by } \mathsf{\dfrac{3}{2}}\large\textsf{ to BOTH  of the SIDES}

\mathsf{x + (-\dfrac{3}{2})+ \dfrac{3}2{}=3+\dfrac{3}{2}}

\large\textsf{CANCEL out: } \mathsf{-\dfrac{3}{2}+\dfrac{3}{2}}\large\textsf{ because that gives you 0}  

\large\textsf{Keep: } \mathsf{3+ \dfrac{3}{2}}\large\textsf{ because that helps solve for your x-value }

\large\textsf{New equation: }\mathsf{x = 3 + \dfrac{3}{2}}

\mathsf{3+\dfrac{3}{2}}

\large\textsf{SOLVE above and you have your ANSWER}

\mathsf{3+\dfrac{3}{2}=\bf \dfrac{9}{2}}

\boxed{\boxed{\large\textsf{Therefore, your answer is: }\mathsf{\bf x = \dfrac{9}{2}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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HELP!!!!!!!
igomit [66]

Substituting the data points into the model:

f(x)= -x2 + 2x -3

f(-2)=-11

f(0)=-3

f(1)=-2

f(3)=-6

f(5)=-18

So A is the right ans.


7 0
2 years ago
Read 2 more answers
Solve 8z + 12 = 5z − 21
Mekhanik [1.2K]
z = -11

Steps:
8z+12 = 5z-21
Subtract 12 from both sides
8z+12-12 = 5z-21-12
Simplify
8z = 5z-33
Subtract 5z from both sides
8z-5z = 5z-33-5z
Simplify
3z = -33
Divide both sides by 3
3z/3 = -33/3
Simplify
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Hope this helps you! (:
-Hamilton1757
3 0
2 years ago
-3(2x-3)+10x=39 what’s the answer
Temka [501]
Decimal form= 7.5 , fraction form = 15/2 , improper fraction= 7 and 1/2
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2 years ago
-x+4x-9=8x+6 what’s X?
Xelga [282]

Answer:

X= -3

Step-by-step explanation:

3x-9=8x+6

3x-8x=6=9

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7 0
2 years ago
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Assume that lines that appear to be tangent are tangent. O is the center of the circle. What is the value of x?
Mashcka [7]

9514 1404 393

Answer:

  x = 20, or 125

Step-by-step explanation:

We cannot tell the angle x is intended to refer to. So, here are two answers. Choose the one you think applies.

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The triangle that includes both marked angles is a right triangle. (The tangent meets the circle at right angles to the radius.) So, the angle x° at the external point is the complement of the marked central angle.

  x° = 90° -70°

  x = 20

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If x° is referring to the exterior angle associated with the isosceles triangle within the circle, then its measure is the supplement of the interior base angle of that triangle. It is ...

  x° = 180° -(180° -70°)/2 = 90° +70°/2

  x = 125

5 0
2 years ago
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