The horizontal asymptote is the value at the y-axis where the graph approaches the line but not necessarily touching it. Hence, the asymptotic characteristic of the graph. The standard form of a function in fraction form is y = (ax^n +...)/(bx^m+...). There are rules to follow to determine the horizontal asymptote of a function.
1) if n = m , then the horizontal equation is y = a/b
2) if n>m, then there is no horizontal equation
3) if n<m, then the horizontal equation is the x axis ; y = 0.

The function given falls on the third rule hence the horizontal asymptote of the function is at y = 0.

8 0

2 years ago

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Solve for x in the equation x squared + 2 x + 1 = 17.

Papessa [141]

Answer:

$x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\$

Step-by-step explanation:

given equation

$x^2 +2x +1 = 17$

subtracting 17 from both sides

$x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\$

the solution for quadratic equation

$ax^2 + bx + c = 0$ is given by

x = $x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a$

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in our problem

a = 1

b = 2

c = -16

$x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4 + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x = ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\$

thus value of x is

$x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\$

3 0

2 years ago

Which of the following values is the solution of x/32=8?<br> a 24<br> b 40<br> c 256<br> d 4

Oduvanchick [21]

Answer:

c) 256

Step-by-step explanation:

https://www.tiger-algebra.com/drill/x/32=8/ This link shows you how it’s done, it’s not some random link, i used the website all the time

4 0

2 years ago

Can someone send me the Proportional Relationships Flocabulary AK?

Lady bird [3.3K]

Answer:

https://www.flocabulary.com/unit/proportional-relationships/

Step-by-step explanation:

i dont have the answer key but you can highlight this and go to the link

6 0

2 years ago