85.4 to it's lowest terms
1 answer:
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Hmmm, as I read it, in year 1, but it doesn't say at the beginning of the year or end, so we'll be assuming is at the beginning of year 1, the amount is 850, how much will it be at the beginning of year 6? namely, 5 years later.
![\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$850\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ t=years\to &5 \end{cases} \\\\\\ A=850[1+0.08(5)]\implies A=850(1.4)](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%5C%5C%5C%5C%0AA%3DP%281%2Brt%29%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%24850%5C%5C%0Ar%3Drate%5Cto%208%5C%25%5Cto%20%5Cfrac%7B8%7D%7B100%7D%5Cto%20%260.08%5C%5C%0At%3Dyears%5Cto%20%265%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D850%5B1%2B0.08%285%29%5D%5Cimplies%20A%3D850%281.4%29)
Answer:
Step-by-step explanation:
Given: Perimeter of base of a pyramid = 12.8 m
Height of the pyramid = 12.5 m
To find: volume of a pyramid
Solution:
Perimeter of base of a pyramid = 12.8 m
As base of the pyramid is a square,
12.8 =
side of a square =
Area of a square (A) =
Height of the pyramid (h) = 12.5 m
Volume of the pyramid =