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Jet001 [13]
3 years ago
15

Which set of polar coordinates describes the same location as the rectangular coordinates (4,-4)

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0
R=4
theta=pi/2

x= r cos(theta) = 4 cos(pi/2) = 4(0) = 0
y = r sin(theta) = 4 sin(pi/2) = 4(1) = 4

(0,4) is the answer.
SOVA2 [1]3 years ago
3 0

Answer:

(4 sqrt2, 315 degrees)

Step-by-step explanation:

apex

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Pls help with stats
aleksklad [387]

Answers:

  1. Exactly 25%
  2. median = 450
  3. Not enough info (see below)
  4. IQR = 24
  5. IQR = 192

=========================================================

Explanations:

  1. By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
  2. The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
  3. There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
  4. Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
  5. Same idea as the previous problem. IQR = Q3 - Q1 = 316.5 - 124.5 = 192
3 0
2 years ago
Graph y=3/4x +5.<br> Click or tap the graph to plot a point
RoseWind [281]
Start at 5 and go up 3 and move 4 to the right

7 0
3 years ago
Read 2 more answers
Find an angle between 0° and 360° that is coterminal with 810°
marysya [2.9K]
90 degrees should be right
4 0
3 years ago
The letters r and Θ represent polar coordinates. perform the following.
nexus9112 [7]

Answer:

\boxed{(x - \frac{1 }{ 2})^{2} + y^{2} = \frac{21 }{ 4}}\\

Step-by-step explanation:

r = \frac{5}{r - cos\theta}\\r^{2} - rcos\theta = 5\\\\

\text{Use the relationships}\\r^{2} = x^{2} + y^{2}; cos\theta = \frac{ x}{r }\\

\begin{array}{ll}x^{2} + y^{2} - r(\frac{x }{r }) = 5 & \text{Made the substitutions } \\x^{2} + y^{2} - x = 5 & \text{Simplified } \\x^{2} -x + y^{2} = 5 & \text{Rearranged } \\x^{2} -x + \frac{1 }{ 4} + y^{2}= 5 + \frac{1 }{ 4} & \text{Completed the square } \\(x - \frac{1 }{ 2})^{2} + y^{2}= \frac{21 }{ 4} & \text{Wrote as sum of squares} \\\end{array}\\\\

\text{This is the equation of a circle with centre at (0.5, 0 ) and radius equal to}\\\frac{\sqrt{21} }{ 2} \approx 2.291\\

\boxed{(x - \frac{1 }{ 2})^{2} + y^{2}= \frac{21 }{ 4}}\\

5 0
2 years ago
I am having trouble understanding square roots . help please<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B81.49%20%5C%5C%20
postnew [5]

I'm going to assume that's a multiplication not a decimal point.

\sqrt{81 \cdot 49} = \sqrt{9 \cdot 9 \cdot 7 \cdot 7} = \sqrt{63 \cdot 63} = 63

Answer: 63


5 0
3 years ago
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