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Rashid [163]
3 years ago
14

A horse runs for 0.25 h and travels 9 mi. The horse’s distance varies directly with the amount of time it runs.

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0
I think it's 45 miles, hope this could help :)
Semmy [17]3 years ago
5 0
First, you want to set up the equation. 

0.25h = 9m
1.5h = x

(x represents the unknown amount of miles.)

Now that you have an equation set up, you cross multiply and get:
0.25x = 9 · 1.5
0.25x = 13.5
x = 54

So the horse runs 54 miles in 1.5h 
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Solve the given equation by completing the square.
Dmitriy789 [7]

Answer:

a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

Step-by-step explanation:

x^{2} +8x = 38

Add 16 to both sides.

x^{2} +8x+16 = 38 + 16

(x+4)^{2} =54

x + 4 = \sqrt{54} or x + 4 = -\sqrt{54}

x+4=3\sqrt{6} or x+4=-3\sqrt{6}

x=-4+3\sqrt{6} or x=-4-3\sqrt{6}

Therefore, a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

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3 years ago
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Step-by-step explanation:

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In order to study the color preferences of people in his town, Andrew samples the population by dividing the residents by region
emmainna [20.7K]

Answer:

Cluster sampling

Step-by-step explanation:

Cluster sampling refers to the sampling that is used in market analysis. It is used when a researcher can not obtain information as a whole for the population but may obtain information through the groups or clusters

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3 years ago
A geologist has collected 5 specimens of basaltic rock and 7 specimens of granite. The geologist instructs a laboratory assistan
MaRussiya [10]

The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:

  • E(X) = 5.25, Var(X) = 0.5966
  • P(X < 6) = 0.9545
  • P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

The mean and the variance are:

\mu = \frac{nk}{N}

\sigma^2 = \frac{nk(N-k)(N-n)}{N^2(N-1)}

We have that:

5 + 7 = 12 rocks, which means that N = 12

9 are chosen, which means that n = 9

7 are granite, which means that k = 7

Question a:

E(X) = \mu = \frac{9\times7}{12} = 5.25

Var(X) = \sigma^2 = \frac{9\times7(12-7)(12-9)}{12^2(12-1)} = 0.5966

Thus:

E(X) = 5.25, Var(X) = 0.5966

Question b:

Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:

P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 4) = h(4,12,9,7) = \frac{C_{7,4}*C_{5,5}}{C_{12,9}} = 0.1591

P(X = 5) = h(5,12,9,7) = \frac{C_{7,5}*C_{5,4}}{C_{12,9}} = 0.4773

P(X = 6) = h(6,12,9,7) = \frac{C_{7,6}*C_{5,3}}{C_{12,9}} = 0.3181

Thus

P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1591 + 0.4773 + 0.3181 = 0.9545

So P(X < 6) = 0.9545.

Question c:

5 of basaltic and 4 of granite: 0.1591 probability.

7 of granite is P(X = 7), in which

P(X = 7) = h(7,12,9,7) = \frac{C_{7,7}*C_{5,2}}{C_{12,9}} = 0.0455

0.1591 + 0.0455 = 0.2046, thus:

P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

A similar question is found at brainly.com/question/24008577

5 0
3 years ago
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