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cluponka [151]
3 years ago
8

How should the number 1.230 x 103 be properly expressed as a decimal?

Mathematics
1 answer:
hoa [83]3 years ago
4 0
Answer: 1,230
Usage of 10^x form is called scientific form and it helps much in science where the calculation unit can vary from very big into very small.
In this case, you are given the number 1.230 x 10^3  and asked to express it in decimal form. Then you just simply need to multiply the number with the 10^3. The calculation  would be: 1.230 x 10^3= 1.230 x 1000= 1230
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Graph this parametric equation<br><br> x = 2t y = t + 5, -2 ≤ t ≤ 3
UNO [17]
We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem. 

We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:

at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8

for the second equation

at t = -2 ; x = 2*-2 =-4
at t=3; x = 2*3 = 6

we group the points based on their original corresponding t's 

(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.
6 0
3 years ago
Use the side-splitter theorem to solve for x in the triangle below.
fiasKO [112]

Answer:

x = 7

Step-by-step explanation:

According to the side-splitter theorem, the two sides of the triangle is divided proportionally if the line that intersects both sides is parallel to the third side of the ∆.

Therefore, based on this theorem, we would have the following:

\frac{x}{21} = \frac{8}{24}

Solve for x

\frac{x}{21} = \frac{1}{3}

Multiply both sides by 21

\frac{x}{21}*21 = \frac{1}{3}*21

x = \frac{21}{3}

x = 7

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2 years ago
How to find the domain and range of numbers
charle [14.2K]

Answer:

m a g i c  t h a t ' s  h o w

4 0
2 years ago
1. (01.02)
Anton [14]

Answer:4

Step-by-step explanation:

f(1)=6(1)+2

=8

g(f(1))=2(8)+4/5

=20/5

=4

6 0
2 years ago
What is the radical form of the expression (2x^4y^5)^3/8
s344n2d4d5 [400]

We are given expression: (2x^4y^5)^{3/8}

Let us distribute 3/8 over exponents in parenthesis, we get

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= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )

We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.

So, we could write it as.

(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )

Now, we could write inside expression of parenthesis in radical form.

xy\sqrt[8]{2x^{3}x^4y^7}

8 0
3 years ago
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