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3 years ago

For any rectangle CMXZ, decide if the statement is always, sometimes, or never true.

Mathematics

1 answer:

Helga [31]3 years ago

5 0

Answer:

C. Sometimes

Step-by-step explanation:

Placement of the c could indicate a rotated rectangle.

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Verify identities Will give BRAINLIST<br><br> cot^2(x) - csc^2(x) = -1<br><br> show steps

san4es73 [151]

Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

What is the sum of 5 5/12+ 4 11/12=?

ANEK [815]

= 9 16/12
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3 years ago

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Which table would it be

Sladkaya [172]

Answer:

Step-by-step explanation:

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4 years ago

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fen

baherus [9]

Answer:

Area = 2500 square feet is the largest area enclosed

Step-by-step explanation:

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fencing

Let x be the length of each box and y be the width of the box

Perimeter of the box= 3(length ) + 4(width)

$200=3x+4y$

solve for y

$200=3x+4y$

$200-3x=4y$

divide both sides by 4

$y=50-\frac{3x}{4}$

Area of the rectangle = length times width

$Area = 3x \cdot y$

$Area = 3x \cdot (50-\frac{3x}{4})$

$A=150x-\frac{9x^2}{4}$

Now take derivative

$A'=150-\frac{9x}{2}$

Set it =0 and solve for x

$0=150-\frac{9x}{2}$

$150=\frac{9x}{2}$

multiply both sides by 2/9

$x=\frac{100}{3}$

$A''=-\frac{9}{2}$

For any value of x, second derivative is negative

So maximum at x= 100/3

$A=150x-\frac{9x^2}{4}$ , replace the value of x

$A=150(\frac{100}{3})-\frac{9(\frac{100}{3})^2}{4})$

Area = 2500 square feet is the largest area enclosed

3 0

3 years ago