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andriy [413]
2 years ago
11

What is the period of the function y = 2 sinx

Mathematics
2 answers:
DanielleElmas [232]2 years ago
5 0

Answer:

The period is 360° ( in radians, the period is 2π)

Step-by-step explanation:

For a sine/cosine (sinusoidal) function in the form

y = ASin(Bx-C) + D, we can say

A is the amplitude

360/B is the period

C is the phase shift

D is the vertical translation

<em>The function given is y = 2Sinx</em>

To find the period, we need 360/B. Since "B" is just "1", the period is

360/1 = 360

Komok [63]2 years ago
3 0

Answer:

The period of the function y = 2sinx is 2\pi

Step-by-step explanation:

The sinosuidal functions have the following form

y = Asin (bx) +k

Where A is the amplitude of the function

k is the vertical displacement

\frac{2\pi}{b} is the period.

In this case we have the function

y = 2sinx

Therefore the amplitude A = 2

The vertical displacement is k = 0

The period is \frac{2\pi}{1} = 2\pi because b=1

Therefore the function completes a cycle every 2\pi

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Answer:

k=3

Step-by-step explanation:

2(4k+3)−13=2(18−k)−13  

2(4k+3)−13=2(18−k)−13

(2)(4k)+(2)(3)+−13=(2)(18)+(2)(−k)+−13

8k+6+−13=36+−2k+−13

(8k)+(6+−13)=(−2k)+(36+−13)

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8k−7+2k=−2k+23+2k

10k−7=23

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10k=30

10k/10=30/10

k=3

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98°

Step-by-step explanation:

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x = 98°

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True or False
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so the answer to your question is 2/5.

hope this helped!!



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