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DochEvi [55]
3 years ago
15

Which of the following is equal to (2x/3 - 7) + 7

Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0
Which of the following is equal to: (2x/3 - 7) + 7
The order of the mathematical operations is PEMDAS.
Therefor the first step you will take is to solve the operation inside the parenthesis.
(2x/3 - 7) =(2x/3 - 7)* 3/3 = 2x/3 - 21/3 = (2x - 21)/3
While adding or subtracting fractions, dont forget to check that each term have the same denominator.

Then the operation outside the parenthesis,

(2x - 21)/3 + 7 = (2x-21)/3 + 7 * 3/3 = (2x - 21)/3 + 21/3 =

(2x - 21 + 21) / 3 = 2x/3

The final answer is D. 2x/3

diamong [38]3 years ago
6 0
<span>The correct answer is D. The number 7 is subtracted from the first term, 2x/3, but then an equal sum is added, and the two effectively cancel each other out. This means that the value of the first expression is essentially 2x/3, which is option D.</span>
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Answer:

1. \frac{\sqrt{13} }{3}

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Step-by-step explanation:

1.

Cot is the trigonometric ratio defined by "adjacent" over "opposite". <em>So, adjacent = 2 and opposite = 3.</em>

By pythagorean theorem, we have the "hypotenuse" as  \sqrt{2^2+3^2}=\sqrt{13}

Csc is defined as the trig ratio "hypotenuse" over "opposite". <em>We know the sides, so Csc \theta = \frac{\sqrt{13} }{3}</em>

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<em>First answer choice is right.</em>

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2.

By definition, Csc \theta is the inverse of Sine \theta. <em>If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:</em>

Csc\theta=\frac{1}{0.3090}\\=3.2362

Third answer choice is right.

3.

By definition tan and cot are inverse of each other. <em>So the value of tan is the reciprocal of the value of cot.</em> We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

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Hurry show your work
Nikolay [14]

Answer: \huge\boxed{\boxed{15}}

Step-by-step explanation:

<u>Given expression</u>

\large\boxed{\frac{12[30 - (9+4^2)]}{|10|-|-6| } }

<u>Simplify the exponents</u>

\large\boxed{=\frac{12[30 - (9+16)]}{|10|-|-6| } }

Simplify values in the parenthesis

\large\boxed{=\frac{12[30 - 25]}{|10|-|-6| } }

\large\boxed{=\frac{12[5]}{|10|-|-6| } }

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Hope this helps!! :)

Please let me know if you have any questions

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