Mercury is the closest planet to the sun.
Venus is second planet. Venus has no moons.
Earth is the third planet. This is the only planet that is known to inhabit life.
Mars is the fourth planet. Mars is called the "red planet" and has two moons.
Jupiter is the fifth planet in our solar system. Jupiter is the biggest planet in our solar system.
Saturn is the sixth planet. It has 31 moons.
Uranus is the seventh planet. It is a greenish-blue planet.
Neptune is the eight planet. On Neptune, temperatures stay colder than -350 Fahrenhiet.
Pluto is no longer a planet, but if you weighed 100 pounds on Earth, then you would weight 7-8 pounds on Pluto. But your mass would be the same.
Answer:
The distance between two protons is 0.1 m
Explanation:
Given that,
The magnitude of force between two protons is,
We know that the charge on proton is,
If F is the electric force between two charges. It is given by the electrostatic force of attraction of repulsion. It is given by :
d is the distance between charges
d = 0.1 m
So, the distance between two protons is 0.1 m. Hence, this is the required solution.
Answer:
L = 0.1379 m = 13.79 cm
Explanation:
The Rayleigh criterion establishes that two objects are separated when the maximum of diffraction for slits coincides with the minimum of the other point, therefore the expression for the diffraction
a sin θ = m λ
the first zero occurs when m = 1
let's use trigonometry to find the angle
tan θ = y / L
as in these experiments the angles are very small
tan θ = sin θ /cos θ = sin θ
sin θ = y / L
we substitute
a y /L = λ
In the case of circular aperture the system must be solved in polar coordinates, for which a numerical constant is introduced
a y / L = 1.22 λ
L = a y / 1.22 λ
We search the magnitudes to the SI system
a = 1.04 cm = 1.04 10⁻² m
y = 9.09 10⁻⁶ m
λ = 562 10⁻⁹ m
let's calculate
L =
L = 1.379 10⁻¹ m
L = 0.1379 m = 13.79 cm
Answer:
E = 0.18 J
Explanation:
given,
Potential of the battery,V = 9 V
Charge on the circuit, Q = 20 m C
= 20 x 10⁻³ C
energy delivered in the circuit
E = Q V
E = 20 x 10⁻³ x 9
E = 180 x 10⁻³
E = 0.18 J
Energy delivered in the circuit is equal to E = 0.18 J
Answer: 0.374 m/s
Explanation: The motion of a loaded spring is assumed to be of a constant acceleration, hence newton's laws of motion is applicable.
Recall from the second law of motion that
F - Fr = ma
Where F = applied force = elastic force = kx
Fr = frictional force =?
u = coefficient of kinetic friction = 0.39
m = mass of block = 2.60kg
g = acceleration due to gravity = 9.8 m/s²
k = elastic constant = 810 N/m
x = 0.0310m
Fr = umg
Fr = 0.39 × 2.60 × 9.8
Fr = 9.94.
F = kx = 810 × 0.0310m = 25.11 N
By substituting the parameters, we have that
25.11 - 9.94 = 2.60 (a)
15.17 = 2.60a
a = 15.17/ 2.60 = 5.84 m/s².
Speed of block (v) =?
Distance covered (s) = 0.0120m
Initial velocity (u) = 0
Recall that
v² = u² + 2as
v² = 2as
v² = 2 × 5.84 × 0.0120m
v² = 0.1400
v = √0.1400
v = 0.374 m/s