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Serggg [28]
4 years ago
7

A skateboarder wants to cross a large playground and notices that there are large shapes painted on its asphalt surface. One sha

pe is a large circle that covers the entire playground. Inscribed in that circle is a square, with one point at the skateboarder’s feet and the other at his destination. The surface is rough and, therefore, friction is present. What path does he follow in order to minimize the work done by nonconservative forces?
Physics
1 answer:
Elden [556K]4 years ago
6 0
<h2>Diagonal of circle </h2>

Explanation:

As the skateboarder wants to cross the play ground . The surface is rough .

As we know , the force of friction is non-conservative force . Thus work is required against this force .

We have formula:

work done = Force x distance (in one direction )

Te force applied cannot be changed , so he is to decrease the distance .

In case of circle , diameter is the minimum distance . Thus he is supposed to move along it .

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List five (5) compounds h2o can form (10 points)
Elena-2011 [213]

Oxygen, hydrogen, sodium, chlorine, lead, iron. Hope this helps!!!


8 0
3 years ago
A figure skater skates across a rink of length 50 m in 12.1 seconds. a. What is the average speed of the skater? (2 points) b. I
melamori03 [73]
(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
v= \frac{S}{t}= \frac{50 m}{12.1 s}=4.13 m/s

(b) The initial speed of the skater is
v_i = 4 m/s
while the final speed is
v_f = 5.3 m/s
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
a= \frac{v_f - v_i}{t}= \frac{5.3 m/s-4.0 m/s}{2.0 s}=0.65 m/s^2

(c) The initial speed of the skater is 
v_i = 13.0 m/s
while the final speed is 
v_f=0
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
2aS=v_f^2 -v_i^2
from which we find
a= \frac{-v_i^2}{2S}= \frac{-(13.0m/s)^2}{2 \cdot 8.0 m}=-10.6 m/s^2
where the negative sign means it is a deceleration.
4 0
4 years ago
A coil of conducting wire carries a current of i(t) = 14.0 sin(1.15 ✕ 103t), where i is in amperes and t is in seconds. A second
Advocard [28]

Answer:

The peak emf in second coil is 1.876 V

Explanation:

Given :

Inductance L = 130 \times 10^{-6} H

The current I(t) = 14 \sin(1.15\times 10^{3} t)

We compare above equation with standard equation,

  I(t) = I_{o} \sin (\omega t + \phi)

From above equation we have,

  \omega = 10^{3} and \phi = 1.15

Find the inductive resistance,

  X_{L} = \omega L

  X_{L} = 10^{3}  \times 130  \times 10^{-6}

  X_{L} = 0.134

The peak emf in second coil is,

   V = I_{o} X_{L}

  V = 14 \times 0.134

  V = 1.876 V

Therefore, the peak emf in second coil is 1.876 V

8 0
3 years ago
Physics question, please help me?
Damm [24]

As we know that block of steel is continue to be in moving state

so here the friction must be kinetic friction between two surface

so we know that formula of kinetic friction must be

F_k = \mu_k mg

now we have

\mu_k = 0.57

mg = 25 N

now from the above equation we have

F_k = 0.57\times 25

F_k = 14.25 N

So here we need atleast 14.25 N force to continue sliding the box now as per given options all forces which are less than 14.25 N is not correct

Hence correct answer must be 18.0 N

<u>D) 18.0 N</u>

7 0
4 years ago
A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done in the process
ivann1987 [24]
Answer: Cannot determine cause we need to know the change of time to calculate the work.

Explanation:

m = 0.5kg

V = 3m/s - 5m/s = -2m/s

P = W/t = Fv

F = ma

W = Fvt

W = (0.5)(9.8)t = 4.9t



4 0
2 years ago
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