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Citrus2011 [14]
4 years ago
7

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much en

ergy was delivered to the circuit?
Physics
1 answer:
dem82 [27]4 years ago
7 0

Answer:

E = 0.18 J

Explanation:

given,

Potential of the battery,V = 9 V

Charge on the circuit, Q = 20 m C

                                        = 20 x 10⁻³ C

energy delivered in the circuit

E = Q V

E = 20 x 10⁻³ x 9

E =  180 x 10⁻³

E = 0.18 J

Energy delivered in the circuit is equal to E = 0.18 J

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Since the KE of this toy at the top of the trajectory would be 0, the velocity of this toy at that moment would also be 0\!.

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