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Neporo4naja [7]
3 years ago
12

if 1.5kg block is pulled across a horizontal surface that has a coefficient of kintic friction of 0.60. if a block is pulled by

a 12n force, what is the net force acting on the block
Physics
1 answer:
inysia [295]3 years ago
4 0

Answer:

3.2N

Explanation:

Given parameters:

Mass of block  = 1.5kg

Coefficient of kinetic friction  = 0.6

Force of pull on block  = 12N

Unknown:

Net force on the block  = ?

Solution:

Frictional force is a force that opposes motion:

  Net force  = Force of pull  - Frictional force

 Frictional force  = umg

   u is coefficient of kinetic friction

   m is the mass

    g is the acceleration due to gravity

 Frictional force  = 0.6 x 1.5 x 9.8  = 8.8N

 Net force  = 12N  - 8.8N  = 3.2N

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A balloon is filled at sea level on a spring day (temperature 20°C) to a volume of 0.500 m3 and then brought at op of Mount Ever
blagie [28]

Answer:

Volume increases

Explanation:

The balloon when filled at sea level being comparatively close to the center of the earth will have higher pressure due to the influence of gravity and when this balloon is taken to the top of the mountain being away from the center of earth, it will experience a lesser pressure due to low gravity where the amount of force exerted by the air on the object is lesser as compared to to that at the sea level.

Therefore, there will be an increase in volume of the balloon as there is expansion of air on the inside of the balloon as a result of low pressure.

There is not  much effect of temperature at both the sea level and the mountain top as the temperature does not impart any energy to the air molecules so as to decrease the volume.

Therefore,there is an increase in the volume of the balloon at the top of the mountain.

Percentage change in volume is given by:

% change = \farc{V - 0.5}{0.5}times 100

8 0
3 years ago
Needing help with this please
Gemiola [76]

Answer:

So A we cant sadly do because we cant draw. B is going to be kinetic. Thats because static friction means it stays in one place, for kinetic it means moving. So it will be 0.05 as the coefficient of the friction. Sadly, I cannot calculate C. You will have to use trigonemetry but I cannot fit that big an explanation.

Answer to A: the free body diagram would be the ski things inclined with gravity, friction, and  air resistance. I except you know which directions

Answer to B: Kinetic friction is the answer.

Answer to C: Find on own, I cannot write super big explanations - use trigonometry.

6 0
3 years ago
The block in the drawing has dimensions L0×2L0×3L0, where L0 =0.5 m. The block has a thermal conductivity of 250 J/(s·m·C˚). In
stira [4]

Answer:

I am sorry but what drawing

3 0
3 years ago
A proton, an alpha particle (a bare helium nucleus), and a singly ionized helium atom are accelerated through a potential differ
ra1l [238]

Answer:

The correct question is:

"Find the energy each gains"

The energy gained by a charged particle accelerated through a potential difference is given by

\Delta U = q\Delta V

where

q is the charge of the particle

\Delta V is the potential difference

For a proton,

q=+e=1.6\cdot 10^{-19}C

And since \Delta V=100 V

The energy gained by the proton is

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

For an alpha particle,

q=+2e=3.2\cdot 10^{-19}C

Therefore, the energy gained is

\Delta U=(3.2\cdot 10^{-19})(100)=3.2\cdot 10^{-17}J

Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)

q=+e=1.6\cdot 10^{-19}C

So the energy gained is the same as the proton:

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

6 0
3 years ago
What is the volume of an object that has a density of 65g/cm3 and a mass of 130g.
lora16 [44]

Density <em>ρ</em> is mass <em>m</em> per unit volume <em>v</em>, or

<em>ρ</em> = <em>m</em> / <em>v</em>

Solving for <em>v</em> gives

<em>v</em> = <em>m</em> / <em>ρ</em>

So the given object has a volume of

<em>v</em> = (130 g) / (65 g/cm³) = 2 cm³

5 0
3 years ago
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