Answer:
If we consider three 20 sided dice, the chance of rolling 15 on each of them is: P = (1/20)³ = 0.000125 (or P = 1.25·10⁻⁴ in scientific notation).
Step-by-step explanation:
<u>We are given the equations: </u>
10x = 10
-5x - 8y = 9
Since we don't have a coefficient of y in the first equation, we will rewrite the first equation as:
10x + 0y = 10
<u>Writing an Augmented matrix for the 2 equations:</u>
10x + 0y = 10
-5x - 8y = 9
![\left[\begin{array}{ccc}10&0|&10\\-5&-8|&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%260%7C%2610%5C%5C-5%26-8%7C%269%5Cend%7Barray%7D%5Cright%5D)
First move the 14 over so 1/3s = 12 then do 12 divided by 1/3, that would be 36 so s=36