Answer: B
Explanation:
It's not the time it took to heat the substance, so that rules out A and C.
This means that we only have to choose between
B. the area of contact
D. the area of the substances
(since everything else in each of those answers are the same)
Area of contact matters more (e.g. an object with greater surface area is exposed to the air more, will lose/gain heat quicker than an object with less surface area).
Answer:
A. 40N
B. 5m/s
Explanation:
A.
Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:
<em>Area of a triangle = (1/2)bh</em>
A=(1/2)*8*10
=40
ANSWER: 40N
B.
<em>Impulse = mass * velocity</em>
40 = 8v
v = 5
ANSWER: 5m/s
Answer:
wave number = 0.3348 * 10⁻⁸ cm⁻¹
Explanation:
Given data:
K = 4.808 * 10^2 N/m
<u>Determine the wave number for the infrared absorption</u>
considering vibrational Spectre
k' = 2n / λ ---- ( 1 )
λ = c / v ----- ( 2 )
v = √k / u --- ( 3 )
where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency, k = force constant, u = reduced mass
u = 1.90415 for D35Cl
Input equations 2 and 3 into equation 1 to get the final equation
K' = 2n/c * √k / u
= ( 2 * 3.14 ) / 2.98 * 10^8 ] * (√ 4.808 * 10^2 / 1.90415 )
= 33.486 * 10⁻⁸ m⁻¹ ≈ 0.3348 * 10⁻⁸ cm⁻¹
