The capacitors are disconnected from the potential difference without allowing them to discharge. They are then reconnected in p arallel with each other, with the positively charged plates connected together. What is the voltage across each capacitor in the parallel combination?
1 answer:
Answer:
net voltage will become half that of initial voltage now
Explanation:
Initially two capacitors are connected across a given voltage difference
So the net charge on the two capacitors is given as
now when these are connected in parallel with no change in charge
then total charge on each plate is given
also we know that
now we will have
so net voltage will become half that of initial voltage now
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Answer:
d = 105 m
Explanation:
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d = 105 m
So, it will cover 105 m before it stops.
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Answer:
W = 0.060 J
v_2 = 0.18 m/s
Explanation:
solution:
for the spring:
W = 1/2*k*x_1^2 - 1/2*k*x_2^2
x_1 = -0.025 m and x_2 = 0
W = 1/2*k*x_1^2 = 1/2*(250 N/m)(-0.028m)^2
W = 0.060 J
the work-energy theorem,
W_tot = K_2 - K_1 = ΔK
with K = 1/2*m*v^2
v_2 = √2*W/m
v_2 = 0.18 m/s
Answer:
6m/s
Explanation:
the original momentum = mass x velocity = 8x (60+10) = 560
momentum after = mass x velocity of the school bag + mass x velocity of the boy = 10x20 + 60x A
200+60A = 560
A=6