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zhenek [66]
3 years ago
9

The capacitors are disconnected from the potential difference without allowing them to discharge. They are then reconnected in p

arallel with each other, with the positively charged plates connected together. What is the voltage across each capacitor in the parallel combination?
Physics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

net voltage will become half that of initial voltage now

Explanation:

Initially two capacitors are connected across a given voltage difference

So the net charge on the two capacitors is given as

Q = C_{eq} V

Q = \frac{C}{2} V

now when these are connected in parallel with no change in charge

then total charge on each plate is given

Q = \frac{CV}{2} + \frac{CV}{2}

Q = CV

also we know that

C_{eq} = 2C

now we will have

V_{net} = \frac{Q_{net}}{C_{eq}}

V_{net} = \frac{CV}{2C} = \frac{V}{2}

so net voltage will become half that of initial voltage now

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