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ddd [48]
3 years ago
8

A wooden plank is leaning against a wall. The bottom of the plank is 3 feet from the wall. Answer each of the following question

s, and show all your work.
(a) Find AC, the approximate length of the plank. Round to the nearest tenth of a foot.

(b) Find BC, the height off the ground where board touches as wall. Round to the nearest foot.

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

AB = ==> distance between the bottom of the plank; and the wall ===> 3 ft.

C ====> 49 degrees

For letter a, to solve for AC:

AC ==> HYPOTENUSE. The angle C is the OPPOSITE side of AB.

use sine :

sin A ===> opposite/hypotenuse

Solve:

sin 49 ====> 3/AC

AC ====> 3 / sin 49

AC ====> 3.96 ft.

For letter b, to solve for BC:

We are now given with the base (3 ft.); and; the hypotenuse (3.96 ft.) so we can use the Pythagorean theorem:

a^2 + b^2 = c^2

Let:

a ===> AB

b ===> BC

c ===> AC

(AB)^2 + (BC)^2 ===> (AC)^2

3^2 + (BC)^2 ===> (3.96)^2

(BC)^2 ===> (3.96)^2 - 3^2

(BC)^2 ===> 6.6816

sqrt (BC)^2 ===> sqrt 6.6816

Answer: BC ===> 2.58 ft.

Hope that helps!!!! : )

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Korvikt [17]

Answer:

The rate at which water leaking is \frac{1}{8} gal/min.

Step-by-step explanation:

Given:

A large container holds 8 gallons of water.

After 56 minutes the container only has 1 gallon of water left.

Now, to find at what rate is the water leaking.

So, water leaked from the container = 8 gallons - 1 gallon = 7 gallons.

Time taken for leakage = 56 minutes.

<em>Now, to get the rate:</em>

\frac{Gallons\ of\ water\ leaked}{Time\ taken\ for\ leakage}

=\frac{7 gallons}{56 minutes}

=\frac{1 gallon}{8 minutes}

The rate = \frac{1}{8} gal/min.

Therefore, the rate at which water is leaking is \frac{1}{8} gal/min.

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