Can you please help me

Mathematics

2 answers:

Mila [183]3 years ago

7 0

Answer:

Step-by-step explanation:

Elan Coil [88]3 years ago

4 0

Answer:

Step-by-step explanation:

The top of the bar tells us how many student had a ranged number of pets in each section.

12 students had 0-4 pets

4 students have 5-9

2 student have 10-14

3 students have 15-19

0 have 20-24

1 have 25-29.

Add up the number of students

12+4+2+3+1=22

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What is 3/5(15k+10)=12k-9 in steps

Diano4ka-milaya [45]

multiply both sides by 5 3(15k+10)=5(12k-9)
get rid of the brackets 45k+30=60k-45
take away 45k to both sides 30=15k-45
plus 45 to both sides 75=15k
divide both by 15 k=5

8 0

3 years ago

Solve, please so it fast

jek_recluse [69]

I Think the answer is 17

6 0

3 years ago

A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

Step-by-step explanation:

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$