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kondor19780726 [428]
3 years ago
11

What's 3(5x + 4) (I’m on a time limit

Mathematics
2 answers:
bonufazy [111]3 years ago
7 0

Answer:

3(5x + 4)

15x + 12

3 · 5x = 15x

3 · 4 = 12

15x + 12

Kazeer [188]3 years ago
4 0

Answer:

15x + 12

Step-by-step explanation:

3(5x + 4)

15x + 12

3 · 5x = 15x

3 · 4 = 12

Combine them:

15x + 12

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A certain large manufacturing facility produces 20,000 parts each week. The manager of the facility estimates that about 1% of t
Slav-nsk [51]

Answer:

198 is the variance for the number of defective parts made each week.      

Step-by-step explanation:

We are given the following in the question:

Number of parts produced each week =  20,000

Percentage of defective parts = 1%

We have to calculate the variance for the number of defective parts made each week.

We treat defective part as a success.

P(Defective part) = 1% = 0.01

p = 0.01

Then the number defective parts follows a binomial distribution .

Formula for variance =

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Thus, 198 is the variance for the number of defective parts made each week.

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3 years ago
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6 0
2 years ago
A consumer survey indicates that the average household spendsμ= $185on groceries each week. The distribution of spending amounts
Vitek1552 [10]

Answer:

P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>0.6)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the average household spent of a population, and for this case we know the distribution for X is given by:

X \sim N(185,25)  

Where \mu=185 and \sigma=25

We are interested on this probability

P(X>200)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>0.6)=1-P(z

7 0
3 years ago
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