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3 years ago

help!!!! It’s missing and I forgot to do but I need the answers 1-4 thank you so much your a life saver

Mathematics

1 answer:

aniked [119]3 years ago

3 0

1. No solution
2. y= -3x/4-5/2
3. x=8+y
4 I can’t really see it

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The average cost of tuition plus room and board at small private liberal arts colleges is reported to be less than $18,500 per t

lys-0071 [83]

Answer:

The null and alternative hypothesis for this study are:

$H_0: \mu=18500\\\\H_a:\mu< 18500$

The null hypothesis is rejected (P-value=0.004).

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is less than $18,500 per term.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average cost of tuition plus room and board at small private liberal arts colleges is less than $18,500 per term.

Then, the null and alternative hypothesis are:

$H_0: \mu=18500\\\\H_a:\mu< 18500$

The significance level is 0.05.

The sample has a size n=150.

The sample mean is M=18200.

The standard deviation of the population is known and has a value of σ=1400.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1400}{\sqrt{150}}=114.31$

Then, we can calculate the z-statistic as:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{18200-18500}{114.31}=\dfrac{-300}{114.31}=-2.624$

This test is a left-tailed test, so the P-value for this test is calculated as:

$P-value=P(z$

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is less than $18,500 per term.

3 0

4 years ago

At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the qua

Nady [450]

Answer:

1) The demand equation is $x=-0.25p+300$

2) The price when no consumers willing to buy this commodity is $1200.

3) The quantity of the commodity would consumers take if it was free is 300 pounds.

Step-by-step explanation:

Given : At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the quantity demanded decreases by 14 pounds.

To find :

1) The demand equation ?

2) At what price are no consumers willing to buy this commodity?

3) According to the above model, how many pounds of this commodity would consumers take if it was free?

Solution :

1) According to question,

p is the unit price and x is the quantity demanded for this commodity in pounds.

Let, $p_1=\$900$ and $x_1=75\text{ pounds}$

and $p_2=\$956$ and $x_2=75-14=61\text{ pounds}$

To find the demand equation we apply two point slope form,

$(x - x_1)=\frac{(x_2-x_1)}{(p_2-p_1)}\times(p-p_1)$

Substitute the values,

$(x - 75)=\frac{61-75}{956-900}\times(p-900)$

$(x - 75)=\frac{-14}{56}\times(p-900)$

$(x - 75)=\frac{-1}{4}\times(p-900)$

$x-75=-\frac{1}{4}p+225$

$x=-\frac{1}{4}p+300$

$x=-0.25p+300$

The demand equation is $x=-0.25p+300$

2) For no consumers,

Substitute x=0 in demand equation,

$0=-0.25p+300$

$0.25p=300$

$p=\frac{300}{0.25}$

$p=1200$

The price when no consumers willing to buy this commodity is $1200.

3) For free,

Substitute p=0 in demand equation,

$x=-0.25(0)+300$

$x=300$

The quantity of the commodity would consumers take if it was free is 300 pounds.

3 0

3 years ago

Michelle’sMichelle‘s grandmother made a quilt that measured 2.44 m long and 1.83 m wide.What is the area of the quilt in square

Vaselesa [24]

$\text{Hello there!}\\\\\text{We know that the length of the quilt is 2.44 m}\\\\\text{We also know that the width of the quilt is 1.83}\\\\\text{To find the area of the quilt, we would multiply length times width:}\\\\2.44\cdot1.83=4.4652\\\\\text{Round to the nearest hundredths}\\\\4.47\,\,\text{m}^2\\\\\text{Always remember than when you're finding area, the unit in the }\\\text{final answer would be squared}\\\\\boxed{4.47\,\,\text{m}^2}$

7 0

3 years ago

Please help write the direct variation. Thank you!

prohojiy [21]

yes the table represents direct variation

the equation is y=3.99x

8 0

3 years ago

A heavy rope, 30 ft long, weighs 0.4 lb/ft and hangs over the edge of a building 80 ft high. Approximate the required work by a

gizmo_the_mogwai [7]

Answer:

180 fb*lb

45 ft*lb

Step-by-step explanation:

We have that the work is equal to:

W = F * d

but when the force is constant and in this case, it is changing.

therefore it would be:

$W = \int\limits^b_ a {F(x)} \, dx$

Where a = 0 and b = 30.

F (x) = 0.4 * x

Therefore, we replace and we would be left with:

$W = \int\limits^b_a {0.4*x} \, dx$

We integrate and we have:

W = 0.4 / 2 * x ^ 2

W = 0.2 * (x ^ 2) from 0 to 30, we replace:

W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)

W = 180 ft * lb

Now in the second part it is the same, but the integral would be from 0 to 15.

we replace:

W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)

W = 45 ft * lb

6 0

3 years ago