(20x^2-19x+3)/5x-1
(400x-19x+3)/5x-1
(381x+3)/5x-1
381x/5x-1 + 3/5x-1
(381/5-381) + (3/5x -3)
(76.2-381) + (3/5x -3)
304.8 + 3/5x-3
101.8 +3/5x
That's what I got. I'm not too sure if it helps though.
256.
The coefficient of just the y term would be 256 because the entire expanded equation looks like this:
y^4+16y^3+96y^2+256y+256
X+2.5 because you dont know her height of last year which would give you the variable X and this year she grew 2.5 inches which would make the equation X+2.5
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Answer:
A: the proposed route is 3.09 miles, so exceeds the city's limit
Step-by-step explanation:
The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...
a^2 = (12-6)^2 +3^2 = 45
a = √45 = 3√5
and
b^2 = (6 -2)^2 +4^2 = 32
b = √32 = 4√2
Then the total length, in grid squares, is ...
3√5 + 4√2 = 6.7082 +5.6569 = 12.3651
If each grid square is 1/4 mile, then 12.3651 grid squares is about ...
(12.3651 squares) · (1/4 mile/square) = 3.0913 miles
The proposed route is too long by 0.09 miles.
