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2 years ago

What is the volume of the cylinder shown below?

Mathematics

2 answers:

seraphim [82]2 years ago

3 0

There is no diagram tho

natali 33 [55]2 years ago

3 0

Answer:

V=1008π units³

Step-by-step explanation:

don’t know what cylendier your talking about but if its the picture below then that’s the answer

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9x -7 = -7 show your work

Irina-Kira [14]

9x-7=-7
+7 +7
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9x= 0
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9 9
x=0

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3 years ago

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What is the answer for this equation or problem? y+6=52 and what does y equal.

Cloud [144]

Answer: y=46

Step-by-step explanation:

Subtract 6 from either side to ensure that the y is alone. This then equals y=52-6.

52-6= 46

So therefore, y=46

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3 years ago

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What are two integers whose product is 0

guapka [62]

Answer:

At least one of the integer must be equal to zero to obtain the product zero

Step-by-step explanation:

we know that

When multiplying integers , if one or both of the integers is 0, then the product is 0.

The multiplication property states that the product of any number and zero is zero.

a*(0)=0

therefore

At least one of the integer must be equal to zero to obtain the product zero

therefore

7 0

3 years ago

Will mark brainliest!! Please answer ASAP

rusak2 [61]

Answer:

y=5

Step-by-step explanation:

y= 5 is always parallel to x axis

8 0

3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago