Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as
For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions
(b) For 200°C and 1.1 atm,
Then the concentration in mg/m3 is
2 atoms because it's H 2 they is saying 2 H's
7 days i think. but not sure about this answer.
Answer:
330.95K
Explanation:
V₁ = 1.2L
T₁ = 25°C = (25 + 273.15)K = 298.15K
P₁ = 1.0 atm
P₂ = 0.74 atm
V₂ = 1.8L
T₂ =?
From combined gas equation,
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Solve for T₂
T₂ = (P₂ * V₂ * T₁) / (P₁ * V₁)
T₂ = (0.74 * 1.8 * 298.15) / (1.0 * 1.2)
T₂ = 397.1358 / 1.2
T₂ = 330.9465K
T₂ = 330.95K or T₂ = (330.95 - 273.15)°C = 57.8°C
Answer:
Explanation:
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