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Marizza181 [45]
2 years ago
14

Please answer ASAP!!!!!

Mathematics
1 answer:
taurus [48]2 years ago
6 0
The answer would be 2. This is because 28 divided by 10 is 2 and 4/5 and 42 divided by 2 and 4/5 is 15 and 7 times 2 plus 1 is 15.
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Which statement correctly describes the diagram? Help it’s 8th grade 3x ams and I really need help ASAP , I already failed twice
Papessa [141]

Answer:

A

Step-by-step explanation:

the first part is definetly triangle b is a reflection of triangle a across the x axis i can't see the bottom part of the last answer but I'm pretty sure A would be correct because triangle c may be a rotation but it's most likely not a reflection of triangle a

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3 years ago
1. Identify a pair of alternate exterior angles.
alisha [4.7K]
First answer is the fourth one, 2 and 6
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3 years ago
Write 7x10x10x10x10 with an exponent
polet [3.4K]

Answer:

7x10^4

Step-by-step explanation:

Please add the thanks and rate me please

6 0
3 years ago
Read 2 more answers
Verify the identitiy:
Advocard [28]

Answer:

\frac{sinx}{1-cos x}     =         cosecx  +  cot x

Step-by-step explanation:

To verify the identity:

sinx/1-cosx = cscx + cotx

we will follow the steps below;

We will take just the left-hand side and work it out to see if it is equal to the right-hand side

sinx/1-cosx

Multiply the numerator and denominator by 1 + cosx

That is;

\frac{sinx}{1-cos x}     =    \frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}

open the parenthesis on the right-hand side of the equation at the numerator and the denominator

sinx(1+cosx) = sinx + sinx cosx

(1-cosx)(1+cosx) = 1 - cos²x

Hence

\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}     =  \frac{sinx + sinx cosx}{1-cos^{2}x }

But 1- cos²x  = sin²x

Hence we will replace  1- cos²x  by  sin²x

   \frac{sinx}{1-cos x}    =       \frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}     =  \frac{sinx + sinx cosx}{1-cos^{2}x }   =  \frac{sinx+sinxcosx}{sin^{2}x }

                             

                                  =\frac{sinx}{sin^{2}x }   +   \frac{sinxcosx}{sin^{2}x }

                                   

                                   =\frac{1}{sinx}   +   \frac{cosx}{sinx}

             

                                   =cosecx  +  cot x

\frac{sinx}{1-cos x}     =         cosecx  +  cot x

Note that;

\frac{1}{sinx}  = cosecx                        

         

 \frac{cosx}{sinx}   =       cot x

                                     

6 0
3 years ago
Please help with these 3 questions
Sever21 [200]

Answer: x = 11

Step-by-step explanation:

2x+5 = 3x-6

2x-3x = -6-5

-x = -11

x = 11

Double-check:
11*2= 22                   11*3=33

22+5 = 27                33-6= 27

4 0
2 years ago
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