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Nana76 [90]
3 years ago
5

To raise money for the music program, your choir sells programs for $.50 and CDs of its music for $5. It costs $.15 to produce e

ach program and $1.75 for each CD. Everything sells for $400 yielding a profit of $265. How many CDs were made?
Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:

60 CDs

Step-by-step explanation:

Given that :

Price of program = $0.5

Price of music = $5

Cost of production :

Program = $0.15 per program

CD = $1.75 per CD

Revenue made= $400

Profit made = $265

Number of CD produced =?

Let Number of CD's = x and program = y

$(0.5y + 5x) = 400

Y = (400 - 5x) / 0.5

y = 800 - 10x

Production :

$(1.75x + 0.15y)

Total cost of production - Revenue made = profit

(1.75x + 0.15y) - (5x + 0.5y) = 265

1.75x + 0.15y - 5x - 0.5y = 265

1.75x - 5x 0.15y - 0.15y = 265

3.25x + 0.35y = 265 - - - (2)

Put y = 800 - 10x in (2)

3.25x + 0.35y = 265

3.25x + 0.35(800 - 10x) = 265

3.25x + 280 - 3.5x = 265

-0.25x = - 15

x = 15/ 0.25

x = 60

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Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

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so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

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A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

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substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

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AC=12\sqrt{2}\ cm

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P=(6\pi+12\sqrt{2})\ cm

simplify

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P=6(\pi+2\sqrt{2})\ cm

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The slope-intercept form given (6,-5) &amp; perpendicular to -5x - 7y = -17.
tatuchka [14]

Answer:

y=\dfrac{7}{5}x-\dfrac{67}{5}

Step-by-step explanation:

<u>Slope-intercept form of a linear equation:</u>

 y=mx+b

where:

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<u>Rearrange</u> the given equation so that it is in <u>slope-intercept form</u>:

\implies -5x-7y=-17

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Therefore, the slope of the given equation is -⁵/₇.

If two lines are <u>perpendicular</u> to each other (at right angles), the <u>product of their slopes</u> will be -1.  Therefore, their slopes will be negative reciprocals of each other.

Therefore, the slope of the line perpendicular to the given equation is:

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\implies b=-\dfrac{67}{5}

<u>Substitute</u> the found slope and the found value of b into the <u>slope-intercept formula</u> to create the equation for the <u>perpendicular line</u>:

\implies y=\dfrac{7}{5}x-\dfrac{67}{5}

Learn more about slope-intercept form here:

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