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baherus [9]
2 years ago
8

20 Points Please Help

Mathematics
1 answer:
stiks02 [169]2 years ago
6 0
1. 31, 37, 43, 49, 55

That’s all I know from this I apologize, I’m only a freshman in hs lol
Good luck and Merry Christmas, happy holidays
You might be interested in
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
Kimi’s dog gives birth to a litter of 4 puppies per year, on average. The relationship between time and the expected total numbe
leva [86]

Step-by-step explanation:

There is no picture showing a graph, I'm very sorry but you have to press the bottom of the screen where it has a paperclip thing and then you have to add a picture from your gallery. I. sorry I couldn't answer you're question but you can redo it with the photo of the graph and I will try to answer it.

8 0
2 years ago
The measure of angle BFE is 120°. Find M angle EFD.
Varvara68 [4.7K]
120 + 120 + X + X = 360
240 + 2X = 360
2X = 120
X = 60
6 0
3 years ago
A car travels at a constant speed.
ad-work [718]

Answer:

see below

Step-by-step explanation:

<h3>Given</h3>
  • Distance is 142.2 m, correct to 1 decimal place
  • Time is 7 seconds,  correct to nearest second
<h3>To find:</h3>
  • Upper bound for the speed
<h3>Solution </h3>

<em>Upper bound for the speed  = upper bound for distance/lower bound for time</em>

  • Upper bound for distance = 142.25 m  (added 0.1/5 = 0.05)
  • Lower bound for time = 6.5 seconds  (subtracted 1/2 = 0.5)

<u>Then, the speed is:</u>

  • 142.25/6.5 = 21.88 m/s
  • 21.88 = 21.9 m/s correct to 1 decimal place
  • 21.88 = 22 m/s correct to nearest m/s

4 0
3 years ago
At the beginning of October, you have $300 in your bank account. You get $25 of allowance each week. Your cousin has $200 in her
lys-0071 [83]

Answer:

20 weeks to have the same amount for both bank accounts

Step-by-step explanation:

brainliest plss?

6 0
2 years ago
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