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mrs_skeptik [129]
3 years ago
9

Convert 1/15 into a decimal correct to 2 decimal places ​

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

\frac{1}{15} = 0.\overline{66}

Step-by-step explanation:

We proceed to show the procedure to calculate the given fraction into a decimal form:

1) Since numerator is less than denominator, the integer component of the decimal number is zero:

\frac{1}{15} = 0.xx

2) We multiply the numerator by 10 and find the tenth digit:

\frac{10}{15} = 0

Then,

\frac{1}{15} = 0.0xx

3) We multiply the fraction in 2) by 10 and find the hundredth digit:

\frac{100}{15} = 6

Then,

\frac{1}{15} = 0.66x

And the remainder is:

r = 100-15\times 6

r = 10

4) We multiply the remainder by 10 and divide this result by the denominator to determine the thousandth digit:

\frac{100}{15} = 6

Then,

\frac{1}{15} = 0.666

This question asks us to write a decimal correct to 2 decimal places, which has the characteristic that is infinite periodical decimal. Then, the result correct to 2 decimal places is:

\frac{1}{15} = 0.\overline{66}

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Answer:

3/2

Step-by-step explanation:

When given two points, we can find the slope from

m= (y2-y1)/(x2-x1)

    = (13 - -2)/(8- -5)

    = (13+2)/(8+5)

    = 15/10

Divide the top and bottom by 5

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Remove the radical from the denominator below. Do not simplify the answer
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I believe the answer is A.

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So, multiply the given problem by (6+sqrt 13). This eliminates the radical from the bottom.

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4 years ago
Find the value of k when 5^-3 + 5^-4 = 5^k x 5^-4
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Answer:

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Step-by-step explanation:

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Given the function f(x) = 4x+2, what is the value of f(3)?
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Answer: f(3) = 14

Concept:

Here, we need to understand the idea of evaluation.  

When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.

Solve:

<u>Given function</u>

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Hope this helps!! :)

Please let me know if you have any questions

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